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Sonja [21]
3 years ago
7

You have driven 30 miles and thats only 2/3 of the way how much further do you have to go'

Mathematics
2 answers:
olga55 [171]3 years ago
4 0
I'm sure it's only 15 miles :)
Hope that helps

lubasha [3.4K]3 years ago
4 0
15 miles as 2/3 is 30 and 1/3 is 30/2 or 15

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13[6^2\(5^2-4^2)+9] simplified form of the expression
dmitriy555 [2]

13[6^2/(5^2-4^2)+9

(25-16)

13[36/9+9]

4+9

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169

8 0
3 years ago
Solve for x: -5bracket(-3x+1)=-45
yawa3891 [41]

Answer:

X=3.33

Step-by-step explanation:

5(-3x+1)=-45

-15x+5=-45

-15x=-45-5

-15x=-50

x=3.33

6 0
2 years ago
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3. The population of a city grows at a rate of 5% per
saul85 [17]

Answer:

the answer is B. 2008

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3 years ago
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The number of polynomials having zeros as -2 and 5 is a)1 b)2 c)3 d)more than 3
WINSTONCH [101]

Answer:

d) More than 3.

Step-by-step explanation:

The polynomial (x - 5)(x + 2)  ( = x^2  - 3x + 10) has zeros of -2 and 5 but so have the polynomials formed by multiplying this by any integer:

- for example 2(x - 5)(x + 2) , 4(x - 5)(x + 2) and so on.

3 0
3 years ago
An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f
Ganezh [65]

Answer:

299.99 miles

Step-by-step explanation:

Since the plane traveled due west,

The total angle is 49.17 + 90

Represent that with θ

θ = 49.17 + 90

θ = 139.17.

Represent the sides as

A = 170

B = 150

C = unknown

Since, θ is opposite side C, side C can be calculated using cosine formula as;

C² = A² + B² - 2ABCosθ

Substitute values for A, B and θ

C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17

C² = 22500 + 28900 - 51000 * Cos 139.17

C² = 51400 - 51000 (−0.7567)

C² = 51400 + 38,591.7

C² = 89,991.7

Take Square Root of both sides

C = 299.9861663477167

C = 299.99 miles (Approximated)

Hence, the distance between the plane and the airport is 299.99 miles

8 0
4 years ago
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