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3 years ago

You have driven 30 miles and thats only 2/3 of the way how much further do you have to go'

Mathematics

2 answers:

olga55 [171]3 years ago

4 0

I'm sure it's only 15 miles :)
Hope that helps

lubasha [3.4K]3 years ago

4 0

15 miles as 2/3 is 30 and 1/3 is 30/2 or 15

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A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If fie

balu736 [363]

Answer:

20,000m²

Step-by-step explanation:

If they jog 12 km/h for half an hour, they have covered.

12 X 0.5 = 6km in 10 circuits. Making 1 perimeter

6 / 10 =0.6 km (600 m).

To determine area we need to convert this perimeter to length and width. We know that it is a rectangle, with 2 equal widths and 2 equal lengths, and the length is twice the width.

So L = 2W

Perimeter = 2W + 2L

600 m = 2W + 2(2W)

600 m = 6W

W = 100 m

L = 200 m

Area = 100 X 200 = 20,000 m²

4 0

3 years ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

Write 5 as a fraction with 5 in the denominator

Ivenika [448]

25/5 is a THE fraction

8 0

3 years ago

Combine the like terms to create an equivalent expression: −7−4p−(−5)

Sloan [31]

Answer:

the answer is -4p-2

8 0