Question

C(x)=x^2+6x+14 find vertex form

Answer 1

Answer:

c(x)=(x+3)^2+5

Step-by-step explanation:

To complete the square, the same value needs to be added to both sides.

So, to complete the square x^2+6x+9=(x+3)^2 add 9 to the expression

C(x) =x^2 +6x + 9 + 14

Since 9 was added to the right-hand side also add 9 to the left-hand side

C(x) +9= x^2 +6x + 9 + 14

Using a^2 + 2ab + b^2=(a+b)^2, factor the expression

C(x)+9= (x+3)^2 +14

Move constant to the right-hand side and change its sign

C(x)=(x+3)^2 +14 - 9

Subtract the numbers

C(x)= (x+3)^2 +5