Answer:
t=5
Step-by-step explanation:
∵ (t,17) lies on (x,y) plane y=x²-3x+7,t>0
∴ 17=t²-3t+7
t²-3t+7-17=0
t²-3t-10=0
t²-5t+2t-10=0
t(t-5)+2(t-5)=0
(t-5)(t+2)=0
t=5,-2
t>0
so t=5
The domain of the function in this case will be for when the denominator is different from zero:
3x ^ 2- 3 = 0
3x ^ 2 = 3
x ^ 2 = 3/3
x ^ 2 = 1
x = + / - 1
Therefore the domain of this function are all reals without including x = 1 and x = -1
Start with a dot on -3 of the y-axis, then use slope 1/1 to go up one and right one, do that until you reach 3 on the x-axis and make a dot, and then just draw a line through both dots.
Answer:
hmmmmmmmmmmmmm idk
Step-by-step explanation:
