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Vaselesa [24]
3 years ago
13

Evaluate lim θ→0 sin(cos 8θ)/sec 5θ.

Mathematics
2 answers:
kenny6666 [7]3 years ago
8 0
In this case, we are given with the expression <span>sin(cos 8θ)/sec 5θ and is asked to evaluate the expression with limit as theta approaches 0. In this case, we just substitute 0 to theta. cos 0 is equal to 1 hence sec 0 is also equal to 1. sin theta is equal to 0.0175. Answer os 0.0175.</span>
Alla [95]3 years ago
5 0

Answer:

The answer is 0.01745

Step-by-step explanation:

Given the limit of the trigonometry function

lim θ→0 sin(cos 8θ)/sec 5θ

To evaluate the limit;

Step 1: substitute the value of θ =0 in the trigonometry function given to have;

lim θ→0 sin(cos 8θ)/sec 5θ

= sin(cos8(0))/sec5(0)

= sin(cos0)/sec0

Since cos 0= 1, the function becomes;

sin1/sec0

Step2: write the secant function as a function of cosine function where

Secθ = 1/cosθ

The resulting equation will become;

Sin1/(1/cos0)

Since cos0 = 1, the equation becomes;

Sin1/(1/1)

= sin1

= 0.01745

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Answer:

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Step-by-step explanation:

y=4x slope is 4

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iren2701 [21]

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3 years ago
the height of a cylinder is three times the diameter of the base . The surface area of thre ylinder is 126pi ft^2. What is thr r
Over [174]
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The surface area (SA) of a cylinder with radius r and height h is:
SA = 2πr² + 2πrh = π(2r² + 2rh)

We have:
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8 0
3 years ago
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Vsevolod [243]

Answer:

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