Round the following 25.635 to 2 d.p 315.239 to 1 dp0.3975 to 3dp 14.989 to 1 dp

1 answer:

6 0

Well, you round up if the digit behind the decimal place is 5 or more and round down if the digit is 4 or less

I guess the first is 25.64, since two decimal places means the hundredths, 3. The digit behind is 5 , meaning that 3 will become a 4.
then 315.2
then 0.398
then 15 because the digit behind 9+ is an 8 greater than 5, which means the 9 is rounded up to 10, which is a one when it passes through the decimal point, making it 15.
sorry if my explanation sucks. I hope this helps.

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9x-y=5 7x-6y=5 Solve the system by the substitution method

qwelly [4]

9x - y = 5
7x - 6y = 5

Solve both equations for one variable. I'll solve for y.

9x - y = 5 Subtract 9x from both sides
-y = -9x + 5 Divide both sides by -1
y = 9x - 5

7x - 6y = 5 Subtract 7x from both sides
-6y = -7x + 5 Divide both sides by -6
y = $\frac{7}{6}$ x - $\frac{5}{6}$

Since both equations equal y, you can set them equal to each other and solve for x.

9x - 5 = $\frac{7}{6}$ x - $\frac{5}{6}$ Multiply both sides by 6 to eliminate the fractions
54x - 30 = 7x - 5 Subtract 7x from both sides
47x - 30 = -5 Add 30 to both sides
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x = $\frac{25}{47}$

Now, plug that x-value into the x of either equation. I'll plug it into 9x - y = 5.

9x - y = 5 Plug in the x-value
9( $\frac{25}{47}$ ) - y = 5 Multiply
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-y = 0.21276595744 (I had to convert it to a decimal) Divide both sides by -1
y = -0.21276595744

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Step-by-step explanation:

Let the the two integers be x and (x + 7)

$\therefore \: x(x + 7) = 98 \\ {x}^{2} + 7x - 98 = 0 \\ {x}^{2} + 14x - 7x - 98 = 0 \\ x(x + 14) - 7(x + 14) = 0 \\ (x + 14)(x - 7) = 0 \\ (x + 14) = 0 \: or \: (x - 7) = 0 \\ x = - 14 \: or \: x = 7 \\ \\ when \: x = - 14 \\ x + 7 = - 14 + 7 = - 7 \\ \\ when \: x = 7 \\ x + 7 = 7 + 7 = 14 \\$

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