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Marina CMI [18]
2 years ago
10

According to the article "Fatigue Testing of Condoms" (Polymer Testing, 2009: 567–571), "tests currently used for condoms are su

rrogates for the challenges they face in use," including a test for holes, an inflation test, a package seal test, and tests of dimensions and lubricant quality (all fertile territory for the use of statistical methodology!). The investigators developed a new test that adds cyclic strain to a level well below breakage and determines the number of cycles to break.
A sample of 20 condoms of one particular type resulted in a sample mean number of 1584 and a sample standard deviation of 607.
1. Calculate and interpret a confidence interval at the 99% confidence level for the true average number of cycles to break. [Note: The article presented the results of hypothesis tests based on the t distribution; the validity of these depends on assuming normal population distributions.]
Mathematics
1 answer:
daser333 [38]2 years ago
6 0

Answer:

99% Confidence interval:  (1196,1973)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Mean, μ = 1584

Standard Deviation, σ = 607

99% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.01} = \pm 2.86  

1584 \pm 2.86(\dfrac{607}{\sqrt{20}} )\\\\ = 1584 \pm 388.18\\ = (1195.82 ,1972.18)\\ \approx (1196,1973)

Thus, there is a 99% chance that it will break in approximately 1196 to 1972

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For f (x) = 3x+1 and g(x) = x? -6,find (7.8)(x).
Vitek1552 [10]
I believe the answer is C
5 0
3 years ago
The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room
tangare [24]
I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. 

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
A = lw\\
600 = (x+5)(x+4)\\
600 =  x^{2} + 9x + 20


Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
600 = x^{2} + 9x + 20\\
x^{2} + 9x - 580 = 0\\
(x + 29)(x - 20) = 0\\
x + 29 = 0, \:\: x - 20 = 0\\
x = -29, x = 20

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).
8 0
3 years ago
Read 2 more answers
Last time, one out of every 4 students in our class was absent. This time, after Jen came back, only one out of every 5 students
VMariaS [17]

Answer: There are 20 students and 4 students are not here today.

Step-by-step explanation:

If the number of students = 4

Let the number of students be 'x'.

Fraction of students absent = \dfrac{x}{4}

If the number of students = 5

Fraction of students absent = \dfrac{x}{5}

And Jen came back,

So, the fraction of student absent is also written as

\dfrac{x}{4}-1

According to question, it becomes,

\dfrac{x}{5}=\dfrac{x}{4}-1\\\\\dfrac{x}{5}=\dfrac{x-4}{4}\\\\4x=5(x-4)\\\\4x=5x-20\\\\4x-5x=-20\\\\-x=-20\\\\x=20

Hence, there are 20 students in our school.

And number of students are not here today is \dfrac{20}{5}=4

3 0
3 years ago
What is the value of the fourth term in the geometric sequence
ivanzaharov [21]

Answer:

a(4) = 15/4

Step-by-step explanation:

Here we're told that the first term is a(1) = 30 and that the common factor r = 1/2.

Thus, the geometric sequence formula specific to this case is

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What is the fourth term?  Let n = 4,

a(4) = 30(1/2)^(4-1), or a(4) = 30(1/2)^(3), or  a(4) = 30(1/8) = 30/8, or, in reduced form,

a(4) = 15/4.

6 0
3 years ago
Can someone pls pls help me ?
Yakvenalex [24]

9514 1404 393

Answer:

  a = 9 meters

Step-by-step explanation:

The perimeter is the sum of the side lengths:

  28 m = a + 2m + a + 8m

  18 m = 2a . . . . . . . . . . . . . . . . subtract 10m, collect terms

  9 m = a . . . . . . . . . . . . . . . divide by 2

The value of a is 9 meters.

8 0
3 years ago
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