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-Dominant- [34]
3 years ago
7

Mia has earned $43.94 of tokens playing games at theamusement center.

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer: She will have 1 dollar and four cents after she buys 12 things.

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

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A certain disease occurs most frequently among older women. Of all age groups, women in their 60s have the highest rate of breas
Law Incorporation [45]

Answer:

The probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

Step-by-step explanation:

Let a set be events that have occurred be denoted as:

S = {A₁, A₂, A₃,..., Aₙ}

The Bayes' theorem states that the conditional probability of an event, say <em>A</em>ₙ given that another event, say <em>X</em> has already occurred is given by:

P(A_{n}|X)=\frac{P(X|A_{n})P(A_{n})}{\sum\limits^{n}_{i=1}{P(X|A_{i})P(A_{i})}}

The disease Breast cancer is being studied among women of age 60s.

Denote the events as follows:

<em>B</em> = a women in their 60s has breast cancer

+ = the mammograms detects the breast cancer

The information provided is:

P(B) = 0.0312\\P(+|B)=0.81\\P(+|B^{c})=0.92

Compute the value of P (B|+) using the Bayes' theorem as follows:

P(B|+)=\frac{P(+|B)P(B)}{P(+|B)P(B)+P(+|B^{c})P(B^{c})}

            =\frac{(0.81\times 0.0312)}{(0.81\times 0.0312)+(0.92\times (1-0.0312)}\\

            =\frac{0.025272}{0.025272+0.891296}

            =0.02757\\\approx0.0276

Thus, the probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

4 0
2 years ago
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