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Igoryamba
3 years ago
6

Write the equilibrium constant expressions for the following equilibria.

Chemistry
2 answers:
Nady [450]3 years ago
7 0

Answer:

1. K = [CF2Cl2] [HCl]^2 / [CCl4] [HF]^2

2. K = [NH3] [HCl] / [NH4Cl]

3. K = [H2SO4] / [SO3] [H2O]

Explanation:

The equilibrium constant for a chemical reaction is simply the ratio of the concentration of the products to that of the reactants

The equilibrium constant for the reactions are written below.

1. CCl4(g) + 2HF(g) ⇌ CF2Cl2(g) + 2HCl(g)

K = [CF2Cl2] [HCl]^2 / [CCl4] [HF]^2

2. NH4Cl(s) ⇌ NH3(g) + HCl(g)

K = [NH3] [HCl] / [NH4Cl]

3. SO3(g) + H2O(1) ⇌ H2SO4(1)

K = [H2SO4] / [SO3] [H2O]

IrinaVladis [17]3 years ago
5 0

Answer:

4. K = [CF₂Cl₂] [HCl]² / [HF]² [CCl₄]

5. K = [NH₃] [HCl]

6. K = 1 / [SO₃]

Explanation:

Equilibrium constant expressions are defined as the ratio between concentrations of products and concentrations of reactants powered to its reaction quotient (Compounds in solid or liquid phase are not taken in the expression).

For the reactions:

4. CCl₄(g) + 2HF(g) ⇌ CF₂Cl₂(g) + 2HCl(g)

Equilibrium expression, K, is:

<em>K = [CF₂Cl₂] [HCl]² / [HF]² [CCl₄]</em>

5. NH₄Cl(s) ⇌ NH₃(g) + HCl(g)

<em>K = [NH₃] [HCl]</em>

6. SO₃(g) + H₂O(l) ⇌ H₂SO₄(l)

<em>K = 1 / [SO₃]</em>

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3 years ago
Determine how many ml of water you need to remove, by evaporation, if you have a 500 ml of 10.20 M HNO3 dilute solution and you
Ludmilka [50]

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<h3>Dilution equation</h3>

Using the dilution equation:

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Read 2 more answers
200 g of solid sodium hydroxide (NaOH) are dissolved in 750 mL of water. What is the concentration of this solution?
Anastaziya [24]

Answer:

6.67 M

Explanation:

Molarity = \frac{mol}{L}

<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>

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<em>Substitute values into the equation.</em>

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