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Igoryamba
2 years ago
6

Write the equilibrium constant expressions for the following equilibria.

Chemistry
2 answers:
Nady [450]2 years ago
7 0

Answer:

1. K = [CF2Cl2] [HCl]^2 / [CCl4] [HF]^2

2. K = [NH3] [HCl] / [NH4Cl]

3. K = [H2SO4] / [SO3] [H2O]

Explanation:

The equilibrium constant for a chemical reaction is simply the ratio of the concentration of the products to that of the reactants

The equilibrium constant for the reactions are written below.

1. CCl4(g) + 2HF(g) ⇌ CF2Cl2(g) + 2HCl(g)

K = [CF2Cl2] [HCl]^2 / [CCl4] [HF]^2

2. NH4Cl(s) ⇌ NH3(g) + HCl(g)

K = [NH3] [HCl] / [NH4Cl]

3. SO3(g) + H2O(1) ⇌ H2SO4(1)

K = [H2SO4] / [SO3] [H2O]

IrinaVladis [17]2 years ago
5 0

Answer:

4. K = [CF₂Cl₂] [HCl]² / [HF]² [CCl₄]

5. K = [NH₃] [HCl]

6. K = 1 / [SO₃]

Explanation:

Equilibrium constant expressions are defined as the ratio between concentrations of products and concentrations of reactants powered to its reaction quotient (Compounds in solid or liquid phase are not taken in the expression).

For the reactions:

4. CCl₄(g) + 2HF(g) ⇌ CF₂Cl₂(g) + 2HCl(g)

Equilibrium expression, K, is:

<em>K = [CF₂Cl₂] [HCl]² / [HF]² [CCl₄]</em>

5. NH₄Cl(s) ⇌ NH₃(g) + HCl(g)

<em>K = [NH₃] [HCl]</em>

6. SO₃(g) + H₂O(l) ⇌ H₂SO₄(l)

<em>K = 1 / [SO₃]</em>

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Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

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B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

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\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

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