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kati45 [8]
2 years ago
9

The energy of the ground state in the bohr model is -13. 6 ev. the energy of the n = 2 is:_______

Chemistry
1 answer:
vlabodo [156]2 years ago
7 0

Bohr's model explained the position of the electron, proton, and neutron in the atom of the element. The energy at the n = 2 level of the atom will be - 3.40 eV.

<h3>What is the principal quantum number (n)?</h3>

The principal quantum number (n) has been the distance of the electron of that atom in the nucleus and its energy in the structure. It can also be said to define the size of the atomic orbit.

n = 2 is the first excited state whose energy is calculated as:

Eₙ = − 13.6 ÷ n² eV

E₂ = - 13.6 eV ÷ 2²

= -3.40 eV

Therefore, -3.40 eV is the energy of electron at n = 2.

Learn more about principal quantum numbers here:

brainly.com/question/14307071

#SPJ4

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Zirconium - 96 isotope is formed from the beta decay of zirconium-97 , Option C is the correct answer .

<h3>What are Isotopes ?</h3>

Atoms are composed of a cloud of electrons surrounding a dense nucleus that is 100,000 times smaller and comprised of protons and neutrons.

The number of protons(i.e., atomic number, "Z") determines the element.

Isotopes are atoms of the same element that have the same number of protons (i.e., atomic number, "Z") but a different number of neutrons, meaning that their mass number, "A", varies.

Naturally occurring zirconium (⁴⁰Zr) is composed of four stable isotopes

One very long-lived radio isotope (⁹⁶Zr), a primordial nuclide that decays via double beta decay with an observed half-life of 2.0×10¹⁹ years

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All have half-lives less than a day except for ⁹⁵Zr (64.02 days), ⁸⁸Zr (83.4 days), and ⁸⁹Zr (78.41 hours).

The primary decay mode is electron capture for isotopes lighter than ⁹²Zr

and the primary mode for heavier isotopes is beta decay.

Therefore Zirconium - 96 isotope is formed from the beta decay of zirconium-97 , Option C is the correct answer .

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