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Mars2501 [29]
3 years ago
10

Which is the best first step and explanation for solving this system of equations?

Mathematics
1 answer:
Volgvan3 years ago
7 0

Answer:

x=-4/9, y=10/3. (-4/9, 10/3).

Step-by-step explanation:

3x+4y=12

3x=2y-8

--------------

2y-8+4y=12

6y-8=12

6y=12+8

6y=20

y=20/6

simplify,

y=10/3

3x=2(10/3)-8

3x=20/3-8

3x=20/3-24/3

3x=-4/3

x=(-4/3)/3

x=(-4/3)(1/3)=-4/9

x=-4/9, y=10/3. (-4/9, 10/3).

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If f(x)=2x-7, then find f(8)​
Artyom0805 [142]

It should be 9. I hope this helps. If it's not 9 then can u please give me a list of your answers to choose from.

5 0
3 years ago
I WILL GIVE BRAINLIEST PLEASE HELP
irina1246 [14]

Answer:

Part I

  • 4.8% compounded semiannually means 4.8%/2 = 2.4% per 6 month period

Part II

  • Period is 6 months, so 2 periods in a year and 2*8 = 16 periods in 8 years

Part III

  • A = $12200*(1 + 0.024)^16

Part IV

  • A = $12200*(1 + 0.024)^16 = $17830.32
6 0
3 years ago
Assume that there is a 4​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
kap26 [50]

Answer:

a) 99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b) 99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4​% rate of disk drive failure in a year.

This means that 96% work correctly, p = 0.96

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk​ drive, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 2

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984

99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b. If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 4

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744

99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

7 0
3 years ago
Fake answers will be reported
algol [13]

Answer:

25,26,27,28,29

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
what are two practical products you could add to find 990 x 37 ; 297 693 2970 6930 69300 6330 29700
VMariaS [17]
First evaluate 990 x 37.
990 x 37 = 36630

Test the given numbers to find the pair that adds up to 36630.
Test 297.
The missing pair will be
36630 - 297 = 36333
Will not work

Test 693.
36630 - 693 = 35937
Will not work

Test 2970.
36630 - 2970 = 33660
Will not work

Test 6930
36630 - 6930 = 29700
This works, because 6930 + 29700 = 36630.

Answer: 6930 and 29700.


8 0
3 years ago
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