12-y=9
3x-y=21
4y-10=2
1/4xy=6
Answer:
wait is that a test if it is cheating
Step-by-step explanation:
well the first one go on the bottom 2 row secound one first row third first row but it is in happpy i am not reall good at math XD third last row forth very happy fifth on unhappy sixth very unhappy seven very unhappy eight on very happy i think i got it i did this before i just don't rembear but i tried
Answer:
p= 2.5
q= 7
Step-by-step explanation:
The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.
Equations in slope- intercept form:
6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)
12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒ y=12/(2p-1)x - (5q-1)/(2p-1)
Slopes equal:
6/(2p-3)= 12/(2p-1)
6(2p-1)= 12(2p-3)
12p- 6= 24p - 36
12p= 30
p= 30/12
p= 2.5
y-intercepts equal:
(2q+3)/(2p-3)= (5q-1)/(2p-1)
(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)
(2q+3)/2= (5q-1)/4
4(2q+3)= 2(5q-1)
8q+12= 10q- 2
2q= 14
q= 7
Answer:
this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).
- we know that
this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1
using the equation of line:
we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e
this is the equation of the tangent at point (-1,1/e)
