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1 answer:
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Answer:
Perimeter = 98 cm
Area = 596
Step-by-step explanation:
Please refer to the attached image for the resultant figure when a quadrant of circle with radius 7 cm is cut from a rectangle of sides 30 cm and 25 cm.
Perimeter of a figure = Sum of all its sides + Perimeter of circle
Quadrant of a circle is one fourth of a circle and there are 4 such quadrant of a circle, so eventually there is one complete circle in this figure.
The sides of this resultant figure = 30 - 14 = 16 cm
and 25 - 14 = 11 cm
So perimeter of this figure = 16 + 11 + 16 + 11 + Perimeter of circle
To find area of this figure = Area of rectangle - Area of circle
Area of rectangle = Length Width
Area of circle =
So, area of figure = 750 - 154 = 596
Answer:
200.96 units
Step-by-step explanation:
Use the formula for the volume of a cone
Plug in the values (=3.14) and multiply them all out
Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
