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dexar [7]
4 years ago
14

Brainiest please help 100 points!

Mathematics
2 answers:
liberstina [14]4 years ago
4 0

Answer:

for the first one stay. second one is reflexive property. third is the alternate interior angles

Step-by-step explanation:

Yuri [45]4 years ago
3 0

Answer:

It is the vertical angles theorem substitution prop and alternate interior angles

Step-by-step explanation:

I'm really bad at explaining this... I hope this helps...

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PLEASE HELP! A class has an average score of 75%. A test is taken with an average score of 60%. The test is graded on a curve so
lord [1]

Answer:

1.032%

Step-by-step explanation:

7 0
3 years ago
can some one explain how to get the answer to this : the record for the most amount of rain in the shortest periodontal time in
Vlad [161]
Do 42 divided by 15 then divided 12 by the awnser. And you do 42 divided by 28 and divided that by 12 I think I'm pretty sure
8 0
3 years ago
-15+6p=5(2p+1)<br> muti step​
konstantin123 [22]
-15+6p= 10p+5
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7 0
3 years ago
The average distance of the sun from Earth is about 1.5 x 108 kilometers.
Nataliya [291]

Answer:

10⁵ billion

Step-by-step explanation:

given that distance from sun to earth

= 1.5 x 10⁸ km    (we need to convert this to millimeters)

= 1.5 x 10⁸ km x  1 million mm per km

= 1.5 x 10⁸ km x  1,000,000 mm/km

= 1.5 x 10⁸ km x  10⁶ mm/km

= 1.5 x 10⁸ x  10⁶

= 1.5 x 10⁽⁸ ⁺ ⁶⁾

= 1.5 x 10¹⁴ mm

also given that a quarter is 1.5mm thick, hence the number of quarters that will span the distance between the sun an earth (i.e 1.5 x 10¹⁴ mm)

= 1.5 x 10¹⁴ mm ÷ 1.5 mm/quarter

= 10¹⁴

= 100,000,000,000,000    (remember that a billion has 9 zeros)

= 100,000 billion

= 10⁵ billion

7 0
4 years ago
Find the two square roots of each complex number by creating and solving polynomial equations.
son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
3 years ago
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