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Ganezh [65]
2 years ago
12

What is the sqaure root of 124

Mathematics
2 answers:
umka2103 [35]2 years ago
6 0
In this case, you just multiply the expression under the root that gave the greatest integer (as you pull the square root of that number). See how I did: 4 multiplied by 31, which gives 124 then pull out the square root of 4, because 31 can not be, because it is a prime number and root would be an irrational number.

\sqrt{124}=\sqrt{4*31}=\sqrt{31}*\sqrt{4}=2\sqrt{31}=~11.14
iVinArrow [24]2 years ago
5 0
Hi, 

<span>Think about your perfect squares: 1, 4, 9, 16, 25, etc. </span>

<span>Therefore, do any of these perfect squares go into 124? Yes, 124 goes into 4, 31 times and therefore we can say: </span>

<span>[ square root of 4 ] [ square root of 31 ] </span>

<span>Now, the square root of 4 is a perfect square which can be simplified down to: </span>

<span>2 square root of 31 <==== FINAL ANSWER </span>
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How many nanoseconds does it take for a computer to perform one calculation if it performs calculations per second?
igor_vitrenko [27]

I believe the correct question is:

6.7*10^7 calc/sec?

 

So:

1/(6.7 x 10^7) = seconds per calculation

1/(6.7 x 10^7) = 100/(6.7 x 10^9) = 14.9 x 10^-9 seconds per calculation = 14.9 ns

Which is approximately 15 ns

 

Answer:

15 ns

7 0
2 years ago
Angle C is inscribed in circle O.
tatuchka [14]

Answer:

The radius of circle O is 8.5 Units

Step-by-step explanation:

Solution

The radius of a circle is refereed to as the  half of the diameter.

Now,

On how to figure out the length of AB, we apply the  Pythagorean's equation or formula which is given below

Thus,

a² + b² = c²

(15)² + (8)² = c²

225 + 64 = c²

√289 = √c²

Then

c = 17

What this shows is that  AB is 17 units.

Since we have gotten the diameter, the next step is to divide into half the know the radius value

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6 0
2 years ago
HELP PLZZ will give brainliest &lt;3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

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