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rusak2 [61]
2 years ago
13

Persons who have been given access to an installation can be counted on to be of no threat. true or false? (antiterrorism scenar

io training, page 3)
Computers and Technology
1 answer:
aliya0001 [1]2 years ago
4 0
<span>The statement that "Persons who have been given access to an installation can be counted on to be of no threat" is false. If they are not honest enough, they could become the dangerous staff the company could ever had because he or she has access to everything, files, information, etc. That is why, in selecting a person to be trusted with such responsibility, he or she undergoes an intensive training.</span>
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scoray [572]

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Versatility refers to the capability of a computer to perform different kinds of works with same accuracy and efficiency.

Explanation:

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Given the following narrative for Bambino’s Pizzeria, list the actors that should be used in the use-case diagram.
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See explaination

Explanation:

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8 0
3 years ago
(Display four patterns using loops) Ask the user to enter an integer to
fomenos

Answer:

Hi There was small mistake. It is working fine for me. When you run from command line - use LoopPattern, not looppatern

import java.util.Scanner;

public class Looppattern {

  public static void main(String[] args) {

      Scanner sc = new Scanner(System.in);

      System.out.println("Enter how man levels you need: ");

      int levels = sc.nextInt();

      System.out.println("\n---------------Pattern A-----------------\n");

      for (int p = 1; p <= levels; p++) {

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              System.out.print(k);

          }

          System.out.println();

      }

      System.out.println("\n---------------Pattern B-----------------\n");

      int r = levels;

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= r; k++) {

              System.out.print(k);

          }

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          System.out.println();

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      System.out.println("\n---------------Pattern C-----------------\n");

      for (int p = 1; p <= levels; p++) { // here incresing

          for (int k = p; k > 0; k--) { // and here decreasing pattern to

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          }

          System.out.println();

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      System.out.println("\n---------------Pattern D-----------------\n");

      r = levels;

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= r; k++) {

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          r--; // decreasing levels

          System.out.println();

      }

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}

Explanation:

4 0
3 years ago
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devlian [24]

Answer:

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3 0
2 years ago
A must decode this code. I guess is not a Cesar. The last line is a email adress.
Pie
It is a text in Polish language.
Powiedz nam w czym jesteś dobry

Magento
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Python
PHP
Zaznaczone?
Teraz wyślij formularz z konsoli przeglądarki:

require('jquery')[WON'T TRANSLATE THIS LINE BECAUSE IT IS IMMORAL-> YES, I AM A PROGRAMMER :)) ]



3 0
2 years ago
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