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maxonik [38]
3 years ago
12

Find the vertex of the parabola whose equation is y= x^2 + 8x + 12

Mathematics
1 answer:
mart [117]3 years ago
7 0
The vertex is (-4,-4)
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Find the equation of the line that passes through (–3, 2) and the intersection of the lines x–2y=0 and 3x+y+5=0.
ipn [44]

Answer:

\frac{19}{7}x+\frac{11}{7}y+5=0

Step-by-step explanation:

the intersection of x-2y=0 and 3x+y+5 is (\frac{-10}{7};\frac{-5}{7})

=> the line : \frac{19}{7}x+\frac{11}{7}y+5=0

7 0
2 years ago
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PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
Charra [1.4K]

Answer:

62.8

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2 years ago
Passes through (3,1) ,perpendicular to y=-3x+2
padilas [110]
Slope would be 1/3 so do rise over run from your point
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2 years ago
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Write 0.43 as a fraction, reduced to the lowest terms​
alexdok [17]

Answer:

43/100

Step-by-step explanation:

It would have to be 43/100 becuase 43 is a prime number, therefore it cannot be simplified.

8 0
3 years ago
Find the missing angles and sides
maria [59]

Step-by-step explanation:

m∠1 = 180-100 = 80

m∠2 = 180-150 = 30

m∠3 = 180-(80+30) = 180 - 110 = 70

using the law of sine :

AC/sin(m∠2) = 5/sin(m∠3) ⇒ AC = sin(m∠2)*(5/sin(m∠3)) = sin(30)×(5÷sin(70))

=2.66044443119

CB/sin(m∠1) = 5/sin(m∠3) ⇒ CB = sin(m∠1)*(5/sin(m∠3)) ⇒ CB = sin(80)×(5÷sin(70)) = 5.240052604588

8 0
2 years ago
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