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3 years ago

7

2 horses ran from the same place from the at same time one horse ran at 2 miles per second and the other ran at a speed for 18 m

iles per second. how far apart were they in 1 minute? in 5 minutes? in 8 minutes?

1 answer:

RSB [31]3 years ago

4 0

Answer:

no horse can run 18 miles per second or even 2 miles per second.

Step-by-step explanation:

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Angles X and Y are congruent. Imported Asset and Imported Asset . Find the degree measure of angle X.

Sphinxa [80]

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One three and six are traingular list all the other triangular numbers up to 36

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4 years ago

John owns shares in a mutual fund and shares of individual stocks in his brokerage account. The Form 1099-DIV from the mutual fu

Bond [772]

Question options:

A. He should report them directly on form 1040

B. He should report them on form 8949 and then on schedule D

C. He should report them on schedule D

D. He is not required to report them until he sells the underlying securities

Answer:

B. He should report them on form 8949 and then on schedule D

Explanation:

John has shares which have capital gains from a mutual fund and a brokerage account. In order to report his taxes, he would need to use the Schedule D(form 1040) for his mutual fund capital gains and the form 8949 for his brokerage capital gains. The brokerage capital gains is then transferred to schedule D.

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3 years ago

The value of y varies inversely with x. what is the value of k when y=12.7 and x=8?

NISA [10]

Answer:

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Step-by-step explanation:

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3 years ago

Y = 4x+1 y=x^2 + 2x - 2 A.6,2 B. 2,6 C. -6,2 D. -6,-2

natta225 [31]

Answer:

The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

Step-by-step explanation:

Given that

$y = 4x + 1 (i)$

$y = x^2 + 2x -2 (ii)$

Now, by susbstituting the value of 'y' from equation i to equation ii, we get

$4x+1=x^2 + 2x -2$

$0=x^2 + 2x -2-4x-1$

$0=x^2 + (2x -4x) +(-2-1)$

$0=x^2 + (-2x) +(-3)$

$0=x^2 -2x -3$

$x^2 -2x -3 = 0 (iii)$

Now by factorization, equation iii can be written as

$x^2 -3x +x -3 = 0$

$x(x -3) + 1(x -3) = 0$

$(x -3)(x +1) = 0$

x = 3 and x = -1

By putting the values of x in equation i, we get

y = 4(3) + 1

y = 12 +1

y = 13

and

y = 4(-1) + 1

y = -4 +1

y = -3

Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

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3 years ago