All categories

4 years ago

Ill give brainliest!!!

Mathematics

1 answer:

ehidna [41]4 years ago

7 0

Given:

The coin wrapper volume = 27,480 mm³.

The coin diameter = 21.18 mm.

There are 50 such coins.

To find:

The thickness (height) of 1 coin.

Solution:

The 50 coins form a cylinder with a volume of 27,480 mm³.

If the diameter is 21.18 mm, the radius of a coin will be $\frac{21.18}{2} = 10.59$ mm.

The volume of a cylinder $= \pi r^{2} h.$

The volume of all 50 coins is given as 27,480 mm³. We need to determine the height of a single coin.

$50( \pi r^{2} h)=27,480.$

$50(3.1415)(10.59^{2} )(h) = 27,480.$

$(17,615.662)(h)=27,480.$

$h= \frac{27,480}{17,615.662} = 1.5599$ mm.

So the thickness of 1 coin is 1.5599 mm.

You might be interested in

Calculators are sold to students for 20 dollars each. Three hundred students are willing to buy them at that price. For every 5

IrinaVladis [17]

If you increase the price 9 times which is 5 dollars more each time you get only 30 students that are willing to buy it. Any more increases will lead to no one wanting to buy it.

8 0

4 years ago

Read 2 more answers

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

3 years ago

In February, Campus Cycle Repair had income from sales of $16,000. Expenses for the month included: rent, $1,250; utilities, $45

djyliett [7]

Answer:

Profit $5700

Step-by-step explanation:

To find loss/profit you subtract the expenses from the total income

Income from sales= $16000

Franchise fee= 5% of sales income

$=\frac{5}{100} *16000=800$

Rent=$1250

Utilities=$450

Wages=$4800

insurance=$300

supplies=$2700

Total expenses

=$1250+$450+$4800+$300+$2700+$800=$10300

Total income

=$16000

Profit

=$16000-$10300=$5700

5 0

4 years ago

Factor the expression completely.

sashaice [31]

It would be A because -2.25*3=-6.75 and -2.25*x=-2.25x giving us are end answer of, -6.75+2.25x

Enjoy!=)

(P.s. I am not 100% sure if this is completely factored but it should be)

6 0

4 years ago

Read 2 more answers

Solve for X: 2^3x + 1 = 2^10 please look at photo and give detailed steps!! thank you

mel-nik [20]

Step-by-step explanation:

since the bases are the same all you have to do is just get the powers of both bases which is 3x + 1 and 10

you're then going to equate 3 x + 1 to 10 and then you have to make +1 cross to the other side making it become -1

you then can subtract 1 from 10 leaving you with 9

and at the LHS we have 3x

we are gonna get rid of the three by dividing it into itself and the 9 at the RHS then X = 3

7 0

3 years ago