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3 years ago

6

A student driver working with uber works for 20 hours. how many units can he/she register for as per 60 hour rule?

1 answer:

Radda [10]3 years ago

7 0

I think it is 3 units

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Caroline was thinking of a number. Caroline doubles it, then adds 13 to get an answer of 15.1. What was the original number?

Alex787 [66]

Answer: 1.05

Step-by-step:
15.1 - 13 = 2.1
2.1 = 1.05

6 0

4 years ago

Read 2 more answers

(1+sint)/(cost)-(cost)/(1-sint)

Evgen [1.6K]

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)}{1-\sin(t)}$

Multiply through the second term by $1+\sin(t)$ :

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)}{1-\sin(t)}\cdot\dfrac{1+\sin(t)}{1+\sin(t)}$

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)(1+\sin(t))}{1-\sin^2(t)}$

Recall that $\cos^2(x)+\sin^2(x)=1$ for all x :

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{\cos(t)(1+\sin(t))}{\cos^2(t)}$

If $\cos(t)\neq0$ , we can cancel a factor of it in the second fraction.

$\dfrac{1+\sin(t)}{\cos(t)} - \dfrac{1+\sin(t)}{\cos(t)}$

and this simplifies to

$\dfrac{(1+\sin(t))-(1+\sin(t))}{\cos(t)} = \boxed{0}$

8 0

3 years ago

Which is a true statement about 7 and 14?

Ksju [112]

7 and 14 can be divided in to two

7 0

4 years ago

I REALLY NEED HELP PLEAAAAAAASE!!!

xenn [34]

I know that 7 is right, so is 8, 9,

4 0

3 years ago

State whether each expression is equivalent.

Dmitry_Shevchenko [17]

$\huge\text{Hey there!}$

$\large\text{State whether each expression is equivalent.}$

$\large\text{In order for you find out which one is equivalent to each expressions, }\\\large\text{you will have to DISTRIBUTE!}$

$\large\text{Option A. }\downarrow$

$\large\text{3(x + 5)}$

$\large\text{3(x) + 3(5)}\\\large\text{= \bf 3x + 15}\\\large\text{5(x + 3)}\\\large\text{5(x) + 5(3)}\\\large\text{= \bf 5x + 15}\\\large\text{\bf 3x + 15 }\bf \neq\large\text{ \bf 5x + 15}$

$\large\text{Option A. is NOT your ANSWER}$

$\large\text{Option B.}\downarrow$

$\large\text{2(3y - 13)}\\\large\text{2(3y) + 2(-13)}\\\large\text{= \bf 6y - 26}\\\large\text{\bf 6y - 26 = 6y - 26}$

$\large\text{Option B. could POSSIBLY be the ANSWER}$

$\large\text{Option C is NOT be your ANSWER because it is way too big.}$

$\large\text{Option D.}\downarrow$

$\large\text{5(q - 3)}\\\large\text{5(q) + 5(-3)}\\\large\text{\bf = 5q - 15}\\\large\text{\bf 15 - 5q}\neq\large\text{\bf 5q - 15}$

$\large\text{Option D. is NOT your ANSWER}$

$\boxed{\boxed{\large\text{Answer: \bf Option B. 6y - 26 and 2(3y - 13)}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

3 years ago