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4 years ago

Identify the point that does not fit the pattern

Mathematics

1 answer:

serg [7]4 years ago

7 0

What points are you talking about ?

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Factor Polynomial 3y^2+y-14

iris [78.8K]

Answer:

Factored Form: ( y - 2 )( 3y + 7 )

Step-by-step explanation:

1. Let us first write down the problem at hand: 3y^2 + y - 14

2. Now let us break this expression into groups:

3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )

3. Factor 3y from 3y^2 - 6y:

3y^2 - 6y ⇒ 3y( y - 2 )

4. Factor 7 from 7y - 14:

7y - 14 ⇒ 7( y - 2 )

5. Substitute Step #3, 4 ⇒ Step #2:

3y( y - 2 ) + 7( y - 2 )

6. Factor common term y - 2:

Answer: ( y - 2 )( 3y + 7 )

4 0

4 years ago

-1x+4x+8-3=16+7x What is x?

Dmitry [639]

Answer:

Your answer is. x= -11/4

7 0

3 years ago

Read 2 more answers

Factor this polynomial completely. 12x2+x-6

jonny [76]

Answer:

(

)

(

−

)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How can I simplify these?

Schach [20]

Answer:

$\large\boxed{343=7\sqrt7}\\\boxed{10\sqrt{96}=40\sqrt6}$

Step-by-step explanation:

$343=7^3=7^2\cdot7\\\\\sqrt{343}=\sqrt{7^2\cdot7}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{7^2}\cdot\sqrt7\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=7\sqrt7\\=====================\\\\96=16\cdot6\\\\10\sqrt{96}=10\sqrt{16\cdot6}=10\sqrt{16}\cdot\sqrt6=(10)(4)\sqrt6=40\sqrt6$

4 0

3 years ago

2 sin^2 (x) -5 sin (x) -3=0

andreyandreev [35.5K]

we have that

$2sin^{2} x-5sin x-3=0$

I. Rewrite the equation by substituting the expression u in for sin x.

$2u^{2} -5u-3=0$

II. Factor the quadratic expression. Rewrite the equation with factors instead of the original polynomial.

$2u^{2} -5u-3=0$ is equal to

using a graph calculator-----> see the attached figure

$(u-3)*(2u+1)=0$

III. Use the zero product property to solve the quadratic equation.

$(u-3)*(2u+1)=0$

(u-3)=0--------------> u=3

(2u+1)=0-------- 2u=-1------> u=-1/2-----> u=-0.5

IV. Rewrite your solutions to Part III by replacing u with sin x.

sin x=3--------> is not the solution (sin x can not be greater than 1)

sin x=-0.50------>is the solution

V. Solve the remaining equations for x, giving all solutions to the equation.

sin x=-0.50

if the sine is negative

then

x belong to the III or IV quadrant

we know that

sin 30°=0.50

the solution for the III quadrant is

x=180°+30°-------> x=210°

the solution for the IV quadrant is

x=360°-30°------> x=330°

5 0

3 years ago