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evablogger [386]
2 years ago
9

HELP PELASE ILL MARK BRAINLIEST AND POINTS!

Mathematics
1 answer:
UNO [17]2 years ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

Both the given lines in graph intersect at point (5 , -2), the point must satisfy both the equations.

and if we check the options, we will observe that D. option has both the equations that satisfy the given conditions.

that is ~

\qquad \sf  \dashrightarrow \: x + y = 3

put y = - 2,we will get :

\qquad \sf  \dashrightarrow \: x - 2 = 3

\qquad \sf  \dashrightarrow \: x = 5

so, 1st equation satifys the condition. let's check out 2nd one.

\qquad \sf  \dashrightarrow \: x + 2y = 1

put y = -2

\qquad \sf  \dashrightarrow \: x + (2 \times  - 2) = 1

\qquad \sf  \dashrightarrow \: x - 4 = 1

\qquad \sf  \dashrightarrow \: x = 5

Hence, we can conclude that the Correct choice is D

You might be interested in
WHAT VALUE IS EQUIVALENT TO (7+3)^2 + (8-1) X 5 EQUAL
sdas [7]

Answer:

135

Step-by-step explanation:

(7+3)^2 + (8-1) * 5

Parentheses first

(10)^2 + (7) * 5

Exponents next

100 + 7*5

Multiply

100 + 35

Add

135

7 0
2 years ago
Factor 9y2 - 12y + 4.<br><br> (3 y - 2)(3 y + 2)<br> (3 y - 4)( y + 1)<br> (3 y - 2) 2
lozanna [386]

Answer:

(y - 2)²

Step-by-step explanation:

9y² - 12y + 4 ← is a perfect square of the form

(ax - b)² = a²x² - 2abx + b²

Compare like terms with 9y² - 12y + 4, thus

a² = 9 ⇒ a = 3

b² = 4 ⇒ b = 2 and

- 2ab = - 2 × 3 × 2 = - 12

Thus

9y² - 12y + 4 = (3y - 2)²

8 0
3 years ago
I need it to be in least to greatest
Reil [10]
-28, -17, 22.4, |-27|
3 0
3 years ago
Read 2 more answers
780 as a percentage of 1.5
Anna [14]
780 as a percentage of 1.5
=\frac{780}{1.5} *100
=52,000 percent of 1.5
4 0
3 years ago
Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
 & (-3,0)

I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
3 years ago
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