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Whitepunk [10]
3 years ago
5

the sum of a number and 9 is multiplied by -2 and the answer is 8 find the number. I know the answer is -5 i need a expression,

or equation. Any of them both HELP
Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0
Y+9x-2=8
That's the answer because y=-5 as yku said so to make an equation yiu could use that and you already solved it so it's Y plus 9 multiplied by -2 is equal to 8 :)
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Matt is running in a 9 mile race over
iren2701 [21]

Answer:54 minutes

Step-by-step explanation:

9 x 5 = 45 then 45+ the.1 minute from each mile so it would be 9 +45 = 54 minutes

4 0
3 years ago
What is the slope-intercept form of the function described by this table?
Andru [333]

Answer:

<em>y = - 3x + 4 </em>

Step-by-step explanation:

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

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y = mx + b  Point-intercept form

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3 years ago
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
3 years ago
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katovenus [111]

Answer:

C: 2x^5

Step-by-step explanation:

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