Answer:
A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. ... Compounds contain different elements in a fixed ratio arranged in a defined manner through chemical bonds.
Explanation:
Adaptations increase the probability of an organism surviving and reproducing in a specific environment.
Answer: Some of the intestinal symptoms elicited by pathogens such as salmonella, shigella, and Escherichia are due to the presence of lipopolysaccharides.
Pathogen associated molecular patterns binds to toll like receptors to elicit a response include lipopolysaccharide or LPS. The bacterial component interaction with the host involves LPS and other components of cell wall causing a septic shock. The triggering of any event of septic shock is directly related to the release of LPS or other bacterial toxins into circulation. Pathogen associated molecular patterns are the molecules which are made by the pathogen and needed for their survival or pathogenic character includes LPS.
Answer:
(a) Frequency of M = 0.64
Frequency of N = 0.04
Frequency of MN= 0.32
(b) Expected frequencies of M = 0.648
Expected frequencies of MN = 0.304
Expected frequencies of N = 0.048
Explanation:
(a) If random mating takes place in the population, then the expected frequencies are
f(L(M)) = p = 0.8
F(L(N)) = q
q= 1 - p
= 1 - 0.8
= 0.2
Frequency of M = p^2 = ( 0.8)^2 = 0.64
Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04
Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32
(b)
F = inbreeding coefficient = 0.05
f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648
f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304
f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048
Answer:
The correct answer is 0.53 meters.
Explanation:
The given density of water is 1025 kg/m^3
Gauge pressure, that is, (P2 - P2) = Po/19
Here Po = 1.013 * 10^5 Pa
= 1.0.13 * 10^5 Pa / 19 = 5331.58 Pa
The change in pressure associated with the depth is given by the formula:
P2 -P1 = ρgh
h = P2 - P1 / ρg
h = 5331.58 Pa / 1025 kg/m^3 * 9.8 m/s^2
h = 0.53 m
Thus, the driver can swim 0.53 meters below water.
