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blondinia [14]
3 years ago
7

Can someone please help me

Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

7.

I) must be true

II) 1 - 1 < 2 - 4 --> false

III) (-10)*(-10) < 1*1 --> false

IV) 1/2 < 2/10 --> false

So (B) 1 must be true

8.

x!·(x + 1)!/2 = (x + 1)!^2 / (2·(x + 1)) = (17 + 1)!^2 / (2·(17 + 1)) = 18!^2 / 6^2

(D)

9.

2·√3·6 = √((2·√3)^2 + 6^2)·h --> h = 3 --> (C)

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Answer:

Step-by-step explanation:

See attachment.

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cestrela7 [59]

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2 years ago
Read 2 more answers
1. Select all values of x that are solutions to the equation: -2(x + 4)(3x - 18) = 0A) -6B) -4C) -2D) OE) 2F) 4G) 6
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\begin{gathered} -2(x+4)(3x-18)=0 \\ \text{There are two factors here which are} \\ -2(x+4)\text{ and} \\ (3x-18) \\ \text{This means, either} \\ 2(x+4)=0 \\ 2x+8=0 \\ 2x=-8 \\ \text{Divide both sides by 2} \\ x=-4 \\ OR \\ 3x-18=0 \\ 3x=18 \\ \text{Divide both sides by 3} \\ x=6 \\ \text{Therefore,} \\ x=-4\text{ or} \\ x=6 \end{gathered}

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