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KengaRu [80]
3 years ago
7

Which theorem can be used to show that AJKL - AMNP?

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

C. ASA Similarity

Step-by-step explanation:

Using the Angle-Side-Angle Similarity Theorem is the only thing we can do because looking above we see that we know two angles and one side. Hence, this can be the only theorem that is fit for these two triangles.

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svet-max [94.6K]

Answer:

13x-9

Step-by-step explanation:

9×(x - 1)

9x - 9 +4x

collect like terms, 9x+4x=13x

4 0
3 years ago
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In ΔOPQ, PQ = 17, QO = 9, and OP = 15. Which statement about the angles of ΔOPQ must be true?
77julia77 [94]

Answer:

All angles are different.

Internal angles can be acute, obtuse, or right angle.

The smallest side is opposite to the smallest angle and the longer side is opposite to the larger angle.

Step-by-step explanation:

Given - In ΔOPQ, PQ = 17, QO = 9, and OP = 15.

To find - Which statement about the angles of ΔOPQ must be true?

Proof -

As given,

In ΔOPQ, PQ = 17, QO = 9, and OP = 15.

As all the sides of the given triangle is different, So the given triangle is a Scalene triangle.

Now,

We know that , In Scalene triangle -

All sides are different.

All angles are different.

Internal angles can be acute, obtuse, or right angle.

The smallest side is opposite to the smallest angle and the longer side is opposite to the larger angle.

6 0
3 years ago
Which of the following represents a function?
Iteru [2.4K]

Functions cannot have different values of y for the same value of x. Now let us check each case one at a time.

<u>First Case:</u> For the same value of x=-1, y has two different values of 7 and 1, which is not allowed in a function. Therefore, the first case is not a function.

<u>Second Case:</u> For the same value of x=-1, y has two different values of -5 and 1, which is not allowed in a function. Therefore, the second case is not a function.

<u>Third Case:</u> For the same value of x=3, y has two different values of 2 and 4, which is not allowed in a function. Therefore, third case is not a function.

<u>Fourth Case:</u> In this case no value of x is same. So, this is a function.

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