Question

A rectangular garden is 20 ft longer than it is wide. Its area is 3500 ft?. What are its dimensions?

Answer 1

Answer:

width of the garden is 50 ft and the length is 70 ft

Step-by-step explanation:

Solution:-

- We will denote the width and and the length of the rectangular garden as:

   Width: x

   Length: x + 20

- We are given the area ( A ) of the garden is 3500 ft^2. We are to determine for what dimensions is the area A = 3500 ft^2.

- Recall that the area ( A ) of a rectangle is the product of length and width as follows:

                      A = Length * width

                      A = x*( x + 20 )

                      3500 = x^2 + 20x

                      x^2 + 20x - 3500 = 0

- Use the quadratic formula to determine the value of ( x ):

                     $x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-20 +/- \sqrt{20^2 - 4*-3500} }{2}\\\\x = \frac{-20 +/- 120 }{2} = -10 +/- 60\\\\x = -70 , 50$

- Ignore the negative value of ( - 70 ft ). Physical impractical to have a negative value. Hence, the width of the garden is 50 ft and the length is 70 ft