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11111nata11111 [884]
3 years ago
15

Make an estimate for 3389+2712. Write a number model to show your strategy. I know the answer. Can someone explain this to me pl

s
Mathematics
1 answer:
Vesna [10]3 years ago
8 0
Basically explain how you managed to get the answer that you got
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[4|16-38|+6]-17•2
Maurinko [17]

\bf \underset{\textit{we start from the innermost}}{\stackrel{\mathbb{PEMDAS}}{[4|16-38|+6]-17\cdot 2}}\implies [4\cdot |\stackrel{\downarrow }{-22}|+6]-17\cdot 2\implies [4\cdot \stackrel{\downarrow }{22}+6]-17\cdot 2 \\[2em] [\stackrel{\downarrow }{88}+6]-17\cdot 2\implies \stackrel{\downarrow }{94}-17\cdot 2\implies 94-\stackrel{\downarrow }{34}\implies 60

3 0
3 years ago
Felix has $100 in the bank and writes a check for $150. He now has
MAXImum [283]

Answer:

Felix has 250 dollars

No change

Lucas has 5 dollars

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please answer this question now. Giving brainliest to anyone who answers
baherus [9]
Line p is perpendicular to S and the equation is y=x +3 which is D
6 0
3 years ago
Pls help, and hurry. i will give anyone brainliest if you give the correct answer.
Anna11 [10]

Answer:

Two answers:

22 ≥ v

OR

v ≤ 22

Step-by-step explanation:

It's the same as solving for a variable in an equality. Imagine it as 17 = v - 5 for a moment. Simplify by subtracting 5 from both sides and re-add the inequality sign. This can be easily done since we are not multiplying or dividing, just adding and subtracting.

4 0
3 years ago
Write an equation of the line that passes through (2 -5) and is parallel to the line 2y=3x+10
andrey2020 [161]

Step-by-step explanation:

Given equation is

2y = 3x + 10

3x - 2y + 10 = 0 .....i)

Any line parallel to line I) is

3x - 2y + k = 0 ......ii)

As the line two passes through the point ( 2 , - 5 ) Now substituting the values

3 * 2 - 2 * ( - 5) + k = 0

6 + 10 + k = 0

16 + k = 0

k = - 16

Now putting the value of k in equation two

3x - 2y + 16 = 0 is the required equation.

Hope it will help :)❤

8 0
3 years ago
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