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sweet [91]
3 years ago
13

How do find the rate of change

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0
Find the slope of the line using the equation (y1-y2)/(x1-x2), which is change in rise over change in run. use any two points, for example (2,-2) and (3,-1). using the formula, (-2-(-1))/(2-3) is the rate of change, giving you -1/-1 as the slope, which is -1. the rate of change is -1.
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F(x) = -2x^3 + 3(x + 2). Does this mean that it's f(3) = -39
Anarel [89]

Answer:

Step-by-step explanation:

lets replace x with 3

f(3)= -2(3)^3+3(3+2)=-2*27+15=-54+15=-39

5 0
2 years ago
The Inverse Function is one-to-one, find a formula for the inverse. (If anyone could explain how to find this mystical formula,
S_A_V [24]
Step 1. Substitute y for f(x) Step 2. Switch x and y. Step 3. Solve for y. Step 4. Substitute f(x) for y.

7 0
3 years ago
What is the area of the figure below? PLEASE HELP ​
viktelen [127]

Answer:

Step-by-step explanation:

This can be broken down into a square and a rectangle.

A=5(5)+(12)(8-5)

A=25+12(3)

A=25+36

A=61 u^2

6 0
2 years ago
Read 2 more answers
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Last Year, a state university received 3,560 applications from boys. Of those applications, 35 Percent were from boys who lived
Rom4ik [11]

Answer:

a)10%=3560/100=356

5%=356/2=178

30%=356X3=1068

35%=1068+178=1246

b)10% of 40%=3560/4=890

100%890x10=8900(answer)

hope this helps


5 0
3 years ago
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