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2 years ago

What is the answer to F(x)=6+3x

1 answer:

4 0

(F)=6+3F

We move all terms to the left:

(F)-(6+3F)=0

We add all the numbers together, and all the variables

F-(3F+6)=0

We get rid of parentheses

F-3F-6=0

We add all the numbers together, and all the variables

-2F-6=0

We move all terms containing F to the left, all other terms to the right

-2F=6

F=6/-2

F=-3

I don’t know if it is right but I hope this helps :)

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How do i do disss pls help

masya89 [10]

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8 0

2 years ago

What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

spayn [35]

Answer: 6,8 and 10

Step-by-step explanation:

To find the length , all we need to find is the distance between each point ,

the formula for calculating distance between two points is given by :

D = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

Let the points be :

A ( -5,-1)

B(-5,5)

C(3,-1)

Calculating the length AB , we have

D1 = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

D1 = $\sqrt{(-5+5)^{2}+(5+1)^{2}}$

D1 = $\sqrt{36}$

D1= 6

Calculating the length AC , we have

D2 = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

D2 = $\sqrt{(3+5)^{2}+(-1+1)^{2}}$

D2 = $\sqrt{64}$

D2 = 8

Calculating the length BC , we have

D3 = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

D3 = $\sqrt{(3+5)^{2}+(-1-5)^{2}}$

D3 = $\sqrt{100}$

D3 = 10

Therefore ,the length of the sides of the triangle are 6,8 and 10

3 0

3 years ago

If you shift the quadratic parent function, f(x)=x^2, right 12 units, what is the equation of the new function?

Kobotan [32]

Answer:

f(x)=(x-12)^2

Step-by-step explanation:

We know that the function f(x+m) equals to the function f(x) translated 'm' times to the left. Therefore, to translate the function f(x) = x^2 twelve units to the right, we have to:

f(x-12) = (x-12)^2

Therefore, the new function is: f(x)=(x-12)^2

7 0

3 years ago

Read 2 more answers

Solve.<br> X = -7<br> 4x - 4y = 12<br> (x,y)

Fynjy0 [20]

Answer:

(-7, -10)

$x=-7\\y=-10$