Answer:
f
−
1
(
x
)
=
√
x
−
16
,
−
√
x
−
16
Step-by-step explanation:
To find the inverse, interchange the variables and solve for y
.
Answer:
CD = 6.385 units
Step-by-step explanation:
Given triangle ABC with right angle at C.
And AB = AD + 6 .
Now, consider the triangle ABC.
⇒ cos(∠BAC) =
(cosФ = adj/hyp)
cos(20) =
.
0.9397 =
(since AB = AD + 6 and AC = AD + CD)
⇒ 0.9397 AD + 5.6382 = AD + CD
⇒ CD = 0.0603 AD + 5.6382. →→→→→ (1)
⇒ sin(∠BAC) =
(sinФ = opp/hyp)
sin(20) =
.
⇒ BC = AB sin(20) . →→→→→(2)
Now, consider the triangle BCD,
sin(∠BDC) = 
⇒ sin(80) = 
CD = 
From (2), CD =
.
⇒ CD = AB (0.3473)
⇒ CD = (AD + 6) (0.3473)
⇒ CD = 0.3473 AD + 2.0838 →→→→→→(3)
Now, (1) →→ CD = 0.0603 AD + 5.6382
(3) →→ CD = 0.3473 AD + 2.0838
⇒ 0.0603 AD + 5.6382 = 0.3473 AD + 2.0838
0.287 AD = 3.5544.
⇒ AD = 12.3847
⇒ From (1), CD = 0.0603(12.3847) + 5.6382
⇒ CD = 6.385 units
Y - (-4) = (5 - (-4))/(2 - (-1)) (x - (-1))
y + 4 = (5 + 4)/(2 + 1) (x + 1)
y + 4 = 9/3 (x + 1)
y + 4 = 3(x + 1)
y + 4 = 3x + 3
y = 3x + 3 - 4
y = 3x - 1
Answer:
A parallel y = 3x-1
B perpendicular y = -1/3x+9
Step-by-step explanation:
y = 3x-4 is written in slope intercept form (y=mx+b) so the slope is 3.
A. If the lines are parallel they have the same slope
m parallel is 3
Using point slope form
y-y1 = m(x-x1)
y-8 = 3(x-3)
Distribute
y-8 = 3x-9
Add 8 to each side
y-8+8 = 3x-9+8
y = 3x-1
This is slope intercept form
B If we want perpendicular lines, the slope is the negative reciprocal
m perpendicular is -(1/3) = -1/3
Using point slope form
y-y1 = m(x-x1)
y-8 = -1/3(x-3)
Distribute
y-8 = -1/3x+1
Add 8 to each side
y-8+8 = -1/3x+1+8
y = -1/3x+9
This is slope intercept form