Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19
Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.
Estimate of sample mean
Estimate of sample standard deviation
to 5 decimal places.
Thus, using the normal probability table,
Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=
0.0712858
Answer:
Step-by-step explanation:
you need to find the distance between points L, M, N to know the length of sides LM, MN, NL
use the distance formula
d= √(x2-x1)² +(y2-y1)², where the points are (x1, y1) and (x2, y2)
LM = √(4-1)² + (-3- -3)² = √3² + 0² = 3
MN = √(1-1)² + (-3-0)² = √0² + 9 = 3
NL = √(4-1)² + (-3-0)² = √3² + 9 = √18 = 3√2
The perimeter is LM+MN+NL = 3+3+3√2 = 6+3√2 ≈ 10.243
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Answer:
(13y + 15) -9y
-117y - 135
Step-by-step explanation:
Distribute -9y to the inside numbers in the parentheses -117y and -135 are not compatible to each other ( because the -135 doesn't have a y ) so that would give you your final answer of:
-117y -135
