The intersection can be parameterized by
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with

.
By Stoke's theorem, the integral of
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along

is equivalent to
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where

is the region bounded by

. The line integral reduces to



In my opinion I think that you have to multiply 13.55 by 8 ounces to find how much she needs to pay.
First, take all the sides you already have, then add them up. (You should get 12) To find the other two sides, do some more simple addition. The 2+3+2 of the the top side add up to six (the bottom side) and sides equal each other so add another three. Total is 12+6+3=21
What's the question? what are you asking?
Answer:
7m+3
Step-by-step explanation:
distribute the - to 7m+1
14m+4-7m-1
now add like terms
7m +3