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Aleks [24]
3 years ago
8

Somebody help me please

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

A triangles angles measure up to 180° so before finding x you must find the missing angle.

So lets make an equation:

180=22+23+a

(a is the missing angle)

So add 22+23=45

180=45+a

Subtract 45 from both sides to isolate A

180-45=45-45+a

135=a

135° is your missing angle

So now we have to find X

A straight line measures to 180° so now we subtract 135°(or a) from 180°

180-135=x

x=45

Therefore X is 45°

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Can you write a real world problem that uses Pythagorean theorem ?
elena-14-01-66 [18.8K]

1) Road Trip: Let’s say two friends are meeting at a playground. Mary is already at the park but her friend Bob needs to get there taking the shortest path possible. Bob has two way he can go - he can follow the roads getting to the park - first heading south 3 miles, then heading west four miles. The total distance covered following the roads will be 7 miles. The other way he can get there is by cutting through some open fields and walk directly to the park. If we apply Pythagoras's theorem to calculate the distance you will get:

(3)<span>2 </span>+ (4)2 =

9 + 16 = C2

√25 = C

5 Miles. = C

Walking through the field will be 2 miles shorter than walking along the roads. .

2) Painting on a Wall: Painters use ladders to paint on high buildings and often use the help of Pythagoras' theorem to complete their work. The painter needs to determine how tall a ladder needs to be in order to safely place the base away from the wall so it won't tip over. In this case the ladder itself will be the hypotenuse. Take for example a painter who has to paint a wall which is about 3 m high. The painter has to put the base of the ladder 2 m away from the wall to ensure it won't tip. What will be the length of the ladder required by the painter to complete his work? You can calculate it using Pythagoras' theorem:

(5)<span>2 </span>+ (2)2 =

25 + 4 = C2

√100 = C

5.3 m. = C

Thus, the painter will need a ladder about 5 meters high.

3) Buying a Suitcase: Mr. Harry wants to purchase a suitcase. The shopkeeper tells Mr. Harry that he has a 30 inch of suitcase available at present and the height of the suitcase is 18 inches. Calculate the actual length of the suitcase for Mr. Harry using Pythagoras' theorem. It is calculated this way:

(18)<span>2 </span>+ (b)2 = (30)2

324 + b2 = 900

B2 = 900 – 324

b= √576

= 24 inches

6 0
3 years ago
Respuesta de la expresión 5 + {4 * 6÷3+1+ [3-(4-8) + (3-2)] }
7nadin3 [17]

Answer:

Vota Trump

Step-by-step explanation:

7 0
4 years ago
What is the standard error of the sampling distribution of sample proportion?.
storchak [24]

Answer:

√ (p(1-p) / n)

Step-by-step explanation:

Standard Error(SE) of the Sample Proportion: √ (p(1-p) / n). Note: as the sample size increases, the standard error decreases.

<h3>---</h3>

Hope this helps you! Feel free to give feedback

5 0
2 years ago
I have 56 dollars in my bank account. I deposit 42 dollars into my account. Then I withdraw 10 dollars. How much money do I have
Artist 52 [7]

Answer:

I have left $88

Step-by-step explanation:

Step two:

Given data

Initial amount= $56

deposited amount= $42

The balance after deposit will be= 56+42

=$98

Step two:

If I withdraw 10 dollars

The new balance will be

=98-10

=$88

Hence I have left $88

3 0
3 years ago
Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)
lozanna [386]
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Distance = \sqrt{(-3-3)^2+(5-2)^2}

Distance = \sqrt{(-6)^2+3^2}

Distance = \sqrt{36+9}

Distance = \sqrt{45}\approx6.7082

6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}
8 0
3 years ago
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