All categories

3 years ago

What is the equation of the line that passes through the point (-6, -6) and has a slope of - 1/3

Mathematics

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

The equation of the line is $y = -\frac{1}{3}x - 8$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Slope of - 1/3

This means that $m = -\frac{1}{3}$

$y = -\frac{1}{3}x + b$

Through the point (-6, -6)

This means that when $x = -6, y = -6$ . So

$y = -\frac{1}{3}x + b$

$-6 = -\frac{1}{3}(-6) + b$

$b + 2 = -6$

$b = -8$

The equation of the line is $y = -\frac{1}{3}x - 8$

You might be interested in

Which expression best represents the difference between triple a number and double a number?

ioda

C. x³ - x²

In word problems, there terms which indicate the mathematical operation that needs to be performed.

difference = refers to the answer in subtraction
triple a number or double a number refers to the number of times a number is multiplied by itself.

in triple a number = a number is multiplied by itself three times.
in double a number = a number is multiplied by itself two times.

It would initially look like this: (x * x * x) - (x * x); to simplify the expression, a number to be multiplied is written down and the number of times it will multiply by itself is noted on the upper right side of the number when we look at it.

Thus: x³ - x² is the correct expression that best describes the word problem above.

8 0

3 years ago

Read 2 more answers

Solve:<br><br> a.x3+x2-8x - 12x+2<br> b. x3-4x2-3x + 18x-3<br> c. x2 + 4x + 4<br> d. x2 - 6x + 9

NeTakaya

<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}$

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}$

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

$(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}$

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}$

Now you can rewrite it as:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}$

Next, multiply:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}$

Next, divide:

$(\frac{f}{g})(x)=(x+2)^2$

And lastly, simplify:

A good tip: $(x+y)^2=x^2+2xy+y^2$

$(\frac{f}{g})(x)=x^2+4x+4$

<h2>Answer:</h2>

<u>The correct option is C. x² + 4x + 4.</u>

7 0

3 years ago

Y=2x+4 I need what the graph would look like. Please help me!

Veseljchak [2.6K]

Answer: I attached a picture of the graph

6 0

2 years ago

Read 2 more answers

A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

Hence, the value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0

3 years ago

When do I learn when what I what what what

aleksandrvk [35]

Answer:

Think???????????????

6 0

3 years ago