What is the equation of the line that passes through the point (-6, -6) and has a slope of - 1/3

Mathematics

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

The equation of the line is $y = -\frac{1}{3}x - 8$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Slope of - 1/3

This means that $m = -\frac{1}{3}$

$y = -\frac{1}{3}x + b$

Through the point (-6, -6)

This means that when $x = -6, y = -6$ . So

$y = -\frac{1}{3}x + b$

$-6 = -\frac{1}{3}(-6) + b$

$b + 2 = -6$

$b = -8$

The equation of the line is $y = -\frac{1}{3}x - 8$

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If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

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T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$