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2 years ago

If a heptagon has an area of 105 in2, what is the measure of one side ?

Mathematics

1 answer:

kumpel [21]2 years ago

4 0

Answer:

5.38 inches

Step-by-step explanation:

The formula for Area of an Heptagon

= A=7/4a²cot(180°/7)

Area = 105in²

Side a = ?

The formula for Side a

= √4A ×tan (180°/7)/7

= √4 × 105 × tan (180°/7) /7

= 5.37536 inches

Approximately = 5.38 inches.

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The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

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Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

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Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

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Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

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