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3 years ago

8

Lindsey needs a jeweler to repair her earrings. Jeweler A is offering her services for an initial $130 in

1 answer:

Diano4ka-milaya [45]3 years ago

5 0

Set the 2 price equations equal to eachother and solve.
130+15x= 142+ 11x
They will be equal after 3 hours

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hichkok12 [17]

Answer:

The relationship between the lengths of the line segments doesn't change. In all the cases, AB = CD and AC = BD.

Step-by-step explanation:

this is the exact answer word for word, so id recommend to put it in your own words

ex. when i move one point the other points move so the lengths stay equal to each other

4 0

3 years ago

Read 2 more answers

How many six-digit odd numbers are possible if the left digit cannot be zero?

melisa1 [442]

We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>

6 0

3 years ago

1. What is the place value of the 1 in 1,234,567,890?

FrozenT [24]

Answer:

The place value of 1 in 1,234,567,890 is <u>1</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>.</u>

4 0

3 years ago

Read 2 more answers

I need to solve this using l'hopital's rule and logarithmic diferentiation.

arlik [135]

Yo sup??

For our convenience let h=x+1

therefore

when x tends to -1, h tends to 0

hence we can rewrite it as

$\lim_{h \to \ 0 } (cos(h))^{(cot(h^2 )}$

This inequality is of the form 1∞

We will now apply the formula

$e^(^g^(^x^)^(^f^(^x^)^-^1^)^)$

plugging in the values of g(x) and f(x)

$e^{lim_{h \to \ 0}{(cot(h)^2(cos(h)-1))}$

express coth² as cosh²/sinh² and also write cosh-1 as 2sin²(h/2)

(by applying the property that cos2x=1-sin²x)

After this multiply the numerator and denominator with h² so that we can apply the property that

$\lim_{x \to \ 0 } sinx/x =1$

Now your equation will look like this.

$e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2)*h^2)/(sin(h)^2*h^2)}$

We will now apply the result

$\lim_{x \to \ 0 } sinx/x =1$

where x=h²

we get

$e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2)}$

we now multiply the numerator and denominator with 4 so that we can say

$\lim_{h^2 \to \ 0 } sin^2(h/2)/(h^2/4) = 1$

$e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2*4/4)}$

$=e^{lim_{h \to \ 0}{((cos(h)^2*2)/(4)}$

Apply the limits and you will get

$e^{cos(0)^2*2/4$

$=e^{1/2}$

Hope this helps.

7 0

3 years ago

The height of a cylinder is 5 centimeters. The diameter of the base of the cylinder is 16 centimeters. Find the lateral surface

soldier1979 [14.2K]

Answer:

Lateral surface area of the cylinder = $251.2 cm^2$

Step-by-step explanation:

Lateral surface area of he cylinder = $2*\pi*r*h$ i.e area of side surface.

$Height(h) = 5 cm$

$Diameter = 16 cm$

$radius(r)= 16/2= 8 cm$

Lateral surface area of the cylinder = $2*\pi *8*5$

$\pi =\frac{22}{7}=3.14$

L.S.A= $2*3.14*8*5$

L.S.A= $251.2 cm^2$

The lateral surface area of the cylinder with radius 8 cm and height 5 cm is $251.2 cm^2$

6 0

3 years ago