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2 years ago

Bryce read 15 books last year. this year he read 21. what was the percent increase?

Mathematics

1 answer:

tangare [24]2 years ago

5 0

Answer:

Step-by-step explanation:

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What is the vertex of a parabola having the equation y = –2(x – 5)2 + 7? Which direction does the parabola open?

Vika [28.1K]

$y = -2(x-5)^2 + 7$

That's vertex form for a parabola $y=a(x-p)^2+q$ and we read off vertex (p,q) as

Answer: Vertex (5,7)

The negative a tells us this is a downward opening parabola (upside down from the usual $y=x^2$ . I remember CUP - Concave Up Positive; here a is negative so not a cup, instead concave down. The same rule applies to second derivatives in calculus so memorize it now and use it later.

Answer: downward

7 0

3 years ago

What is the solution to log (9x)-log 3 = 3?

xeze [42]

Answer:

The solution x = $\frac{e^{3} }{3}$

Step-by-step explanation:

Step 1:-

Given $log(9 x) -log 3 =3$

we have to use formula $log a-log b=log\frac{a}{b}$

$log(9 x)- log 3 = log(\frac{9 x}{3} )$ = $3$

Again by using formula $log a =b$

$a = e^{b}$

so $\frac{9 x}{3} =e^{3}$

step 2:-

$3 x = e^{3}$

$x = \frac{e^{3} }{3}$

The solution of given problem is $x=\frac{e^3}{3}$

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3 years ago

The function, f(x)=70n-400, models the profit of the instructor of a guitar class per month, where n is the number of students e

zimovet [89]

profit=f(x)

so solve for f(x)=1000

1000=70n-400

add 400 to both sides

1400=70n

divide both sides by 70

20=n

20 students need to be enrolled to make a profit of 1000.00

4 0

2 years ago

Tyler's brother earns $12 per hour. The store offers him a raise - a 5% increase per hour. After the raise, how much will Tyler'

Natali [406]

Answer: $12*0.05=$0.60. Then, add this amount to his current hourly rate. So he now makes $12.60.

7 0

2 years ago

Solve the inequality. Check your solutions.

Komok [63]

The inequality is

$7- \frac{2}{b}\ \textless \ \frac{5}{b}$

write 7 as 7b/b to have all the expressions in common denominator:

$\frac{7b}{b} - \frac{2}{b}\ \textless \ \frac{5}{b}$

$\frac{7b-2}{b} \ \textless \ \frac{5}{b}$

$\frac{7b-2}{b}- \frac{5}{b}\ \textless \ 0$

$\frac{7b-2-5}{b}\ \textless \ 0$

$\frac{7b-7}{b}\ \textless \ 0$

$\frac{7(b-1)}{b}\ \textless \ 0$

here b=1 is a root and b=0 is not in the domain of the expression, but it still has an effect in the sign of the expression.

the sign table of $\frac{7(b-1)}{b}$ is :

+++++++[0] --------[1] +++++

this means that for values of b to the left of 0 and to the right of 1, the expression is positive, and for values of b in (0, 1), the expression is negative.

that is $\frac{7(b-1)}{b}\ \textless \ 0$ for b∈(0, 1)

Answer: (0, 1)

8 0

3 years ago