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aliina [53]
3 years ago
11

Which expression is equivalent to this polynomial? 6x2 + 10x − 56=

Mathematics
2 answers:
Semmy [17]3 years ago
7 0

Step-by-step explanation:

A 4x - 16 - 6x2 - 6x + 40

Solving like terms

-6x2 - 2x + 24

B 3x2 + 5x - 28 + 3x2 - 5x - 28

Solving like terms

6x2 - 64

C 4x - 16 + 6x2 + 6x - 40

Solving like terms

6x2 + 10x - 56

Option C is the correct answer

hammer [34]3 years ago
4 0
2nd one maybe I’m not to sure srry
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What’s the absolute value of 8
Anuta_ua [19.1K]

Answer:

8

Step-by-step explanation:

Absolute value is always the positive value of a number.

8 0
3 years ago
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Help due in 45 minutes!!
Nat2105 [25]

Answer:

(14,-1)

Step-by-step explanation:

okay so first you need to use the "x=4y+10" in the first equation.

Rewrite as

3(4y+10) +11y=7

Distribute the 3(4y+10)

Rewrite as

12y+30

You'll have the equation

12y +30 +11y= 7

Subtract the 7 from both sides

12y+30+11y-7= 0

Combine like terms

23y+23=0

the best thing to do here is divide the equation by 23.

23/23 = 1

you'll have

y + 1 = 0

this simplifies to

y= -1

use this y value to solve for x

the easiest way to do this is start with the equation

x = 4y +10

Substitute the y for -1

x = -4(-1) +10

x = 4 +10

x = 14

the solution point is

(14,-1)

3 0
3 years ago
Write a rule for the nth term of the arithmetic sequence. Then graph the first six terms of the sequence. a6=-12 a12=-36
denis-greek [22]

Answer:

We need to find the first term.  We can use the formula

an = a1 + d(n - 1)

to solve for a1.  We already know the 12th term, a12, common difference, d, and nth sequence, n.

a12 = -36

d = -4

n = 12

-36 = a1 - 4(12 - 1)

-36 = a1 - 44

8 = a1

The first term is 8.  Therefore, your formula is

an = 8 - 4(n - 1)

an = -4n + 12

Then use this formula to graph.

n is the independent variable.

an is the dependent variable.

Your graph will be a line.

n    |       an

___________

1          8

2          4

3          0

4         -4

5         -8

6         -12

Step-by-step explanation:

give me brainliest.

3 0
3 years ago
Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!
Thepotemich [5.8K]

Answer:

First, a absolute value function is something like:

y = f(x) = IxI

remember how this work:

if x ≥ 0, IxI = x

if x ≤ 0, IxI = -x

Notice that I0I = 0.

And the range of this function is all the possible values of y.

For example for the parent function IxI, the range will be all the positive reals and the zero.

First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.

Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:

y ≥ A

Or all the real values equal to or larger than A.

if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:

y ≤ A

Or "All the real values equal to or smaller than A"

5 0
3 years ago
Which statement is true regarding the functions f(x) and g(x)?
sergij07 [2.7K]
F(x) and g(x) are common fractures

Yuh??
5 0
3 years ago
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