Answer:
Math
Step-by-step explanation:
12
<h3>
Answer: 144</h3><h3>
Step-by-step explanation:</h3><h3 />
Since, the first 9 multiple of 4 starts from 0 are,
0, 4, 8, 12, 16, 20, ................
Which is an AP,
Having the first term, 
And, the successive difference, d = 4,
Since, the sum of the n term of an AP,
![S_n = \frac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D)
Hence the sum of 9 term of the above AP,
![S_9 = \frac{9}{2}[2\times 0 + (9-1)\times 4]](https://tex.z-dn.net/?f=S_9%20%3D%20%5Cfrac%7B9%7D%7B2%7D%5B2%5Ctimes%200%20%2B%20%289-1%29%5Ctimes%204%5D)



You'll need to use parentheses to indicate what is under the first radical sign and what is not. Did you mean radical(36a) or just radical 36?
I will assume that you meant radical(36a).
Then you have [radical(36a}*(b^4)*c^5.
This comes out to 6sqrt(a)*b^4*c^5.
X could represent anything 3 & up for A. for b , x could be 1 or greater