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gizmo_the_mogwai [7]
3 years ago
13

Denise makes three times as many chocolate cupcakes as vanilla cupcakes. She also makes three dozen strawberry cupcakes. If Deni

se makes 132 cupcakes, how many dozen chocolate cupcakes does she make?
Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

6 dozens

Step-by-step explanation:

Vanilla, v = x

Chocolate, c = 3x

Strawberry, s = 3 dozens = 36

Total cupcakes = 132

Hence,

x + 3x + 36 = 132

4x = 96

x = 96 / 4

x = 24

Chocolate = 3 * 24 = 72

Dozens of chocolate = 72 /12 = 6 dozens

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Ariel made 108 cupcakes. If 32 of them are chocolate, what percent of the cupcakes are vanilla?
Leni [432]

Answer:

About 70%

Step-by-step explanation:

Subtract the number of chocolate cupcakes from the total cupcakes.

108-32=76

76 cupcakes are vanilla.

Divide 76/108

76/108

70.3%

About 70% of the cupcakes are vanilla.

(I don't know if you are allowed to use a calculator in your class, but I did)

8 0
3 years ago
Matthew deposits $400 into an account that earns 7% interest compounded quarterly. What is the balance in his account after 10 y
user100 [1]

Answer:

$787

Step-by-step explanation:

In terms of interest

To find the multiplier using '7% more' continues as follows

100% + 7% = 107%

107/100 = 1.07 (multiplier)

Add the ten years as a power to the multiplier

1.07^10

And multiply this by $400

400 x 1.07^10 = 786.860542916

To the nearest dollar = $787

7 0
3 years ago
Read 2 more answers
What is the area of triangle abc? Pls explain thoroughly.
Andru [333]

Answer:

0.25 ( I guess)

Step-by-step explanation:

use 1/2 (b*h) formula

8 0
3 years ago
A baseball player reaches first base 20% of the times he is at bat. Out of 70 times at bat, about how many
leva [86]

Roughly 14 times as 20% of 70 is 14.

4 0
3 years ago
in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
4 years ago
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