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gizmo_the_mogwai [7]
3 years ago
13

Denise makes three times as many chocolate cupcakes as vanilla cupcakes. She also makes three dozen strawberry cupcakes. If Deni

se makes 132 cupcakes, how many dozen chocolate cupcakes does she make?
Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

6 dozens

Step-by-step explanation:

Vanilla, v = x

Chocolate, c = 3x

Strawberry, s = 3 dozens = 36

Total cupcakes = 132

Hence,

x + 3x + 36 = 132

4x = 96

x = 96 / 4

x = 24

Chocolate = 3 * 24 = 72

Dozens of chocolate = 72 /12 = 6 dozens

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Alex73 [517]

Answer:

a) 0.1587

b) 0.023

c) 0.341

d) 0.818

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 515

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(score greater than 615)

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P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%

b) b) P(score greater than 715)

P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)

Calculating the value from the standard normal table we have,

1 - 0.977 = 0.023 = 2.3\%\\P( x > 715) = 2.3\%

c) P(score between 415 and 515)

P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%

P(415 \leq x \leq 515) = 34.1\%

d) P(score between 315 and 615)

P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%

P(315 \leq x \leq 615) = 81.8\%

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4 years ago
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I need help! Math question
iren2701 [21]
Again, a spreadsheet or suitable calculator makes this short work.

The sum is 184.

_____
The terms being summed are ...
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