All categories

3 years ago

Nancy needs at least 1000 gigabytes of storage to take pictures and videos on her upcoming vacation. She

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

The answer to this question can be defined as follows:

In option 1, She buys 4 memory cards.

In option 2, The cost of memory is $40

Step-by-step explanation:

Given:

Available space is = 105 GB

required space = 1000 GB

256 GB memory cost $10.

Find needed memory:

= 1000 GB - 105 GB

= 895 GB

∴ the available memory is 256 GB.

∵ 256 × 4 = 1024 GB

The total memory she have = 1024 + 105 = 1129 GB

And she needs to buy 4 memory cards.

The cost of the four memory cards is= 4 ×10 = $40.

IgorC [24]3 years ago

4 0

Answer:

The total memory she have = 1024 + 105 = 1129 GB

And she needs to buy 4 memory cards.

The cost of the four memory cards is= 4 ×10 = $40.

Step-by-step explanation: The total memory she have = 1024 + 105 = 1129 GB

And she needs to buy 4 memory cards.

The cost of the four memory cards is= 4 ×10 = $40.

You might be interested in

Tyler and Pearl went on a 20km bike ride that lasted for 3 hours. Because of steep hills or the trail, they walked for most of t

noname [10]

Answer: 1 hour

Step-by-step explanation:

Let the distance they walked be $d_1$ in time $t_1$ and the distance they walked be $d_2$ in time $t_2$ ,then

Walking speed= $\frac{d_1}{t_1}=4$

$\\\Rightarrow\ d_1=4t_1$

Riding speed= $\frac{d_2}{t_2}=12$

$\\\Rightarrow\ d_2=12t_1$

Also the total time taken=3 hours

∴ $t_1+t_2=3\\\Rightarrow\ t_2=3-t_1$ ...(1)

Since the total distance= 20 km

∴ $d_1+d_2=20\\\Rightarrow4t_1+12t_2=20\\\Rightarrow4t_1+12(3-t_1)=20..............[\text{from (1)}]\\\Rightarrow4t_1+36-12t_1=20\\\Rightarrow-8t_1=-8\\\Rightarrow\ t_1=1$

Thus, the they spent 1 hour time in walking.

7 0

2 years ago

If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)

Elden [556K]

To solve this problem you must apply the proccedure shown below:
1. You have the following functions given in the problem above:
$f(x)=x-6 
$ and $g(x)=x1/2(x+3)=x(x+3)/2$ <span>
2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
</span> $g(x)*f(x)=(x-6)*x(x+3)/2$ <span>
3. Applying the distributive property, you have:
</span> $g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2$
$g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$
The answer is: $g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$