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kramer
2 years ago
5

I am a multiple of 30, if you round me to the nearest hundred, you can get 400, what number could I be? *

Mathematics
1 answer:
storchak [24]2 years ago
3 0

Answer and Step-by-step explanation:

The answer can be 360 or 390, as both of these can round up to the nearest hundred and become 400.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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1 year ago
How 2 do?<br><br> (n)(n+7)(n+8)
madreJ [45]

Answer:

n^{3} + 15n^{2} + 56n

Step-by-step explanation:

First FOIL  (n + 7)(n + 8) and then distribute n

(n + 7)(n + 8) = n^{2} +15n + 56

 n (n^{2} +15n + 56)

= n^{3} + 15n^{2} + 56n

6 0
2 years ago
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Lelechka [254]

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3 0
3 years ago
3n + 14= --4 What is the answer
andre [41]

Answer: n = -6

Step-by-step explanation:

3n+14=-4

Subtract 14 from both sides.

3n+14-14=-4-14

Simplify

3n=-18

Divide both sides by 3

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5 0
2 years ago
Read 2 more answers
The quotient of (x⁴+ 5x³ 3x - 15) and (x³ - 3) is a polynomial. What is the quotient?
lesya [120]

Answer:

x+5 (under assumption you meant to do -3x

Step-by-step explanation:

you can use long division.

Take the leading coefficient x^4 and divide it by x^3. This results in x which is going to be the first part of you quotient. Now take that x and multiply it by the divisor (x^3 - 3). This gives you x(x^3 - 3) = x^4 - 3x. Now subtract that x^4 - 3x from the original polynomial and repeat this until you can't divide anymore

x^4+5x^3-3x-15 - (x^4-3x) = 5x^3-15\\x^3/5x^3=5\\5(x^3-3) = 5x^3-15\\5x^3-15-(5x^3-15) = 0\\\\x+5

6 0
2 years ago
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