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ehidna [41]
3 years ago
5

What is the domain of the profit function P=6t+10s?

Mathematics
2 answers:
mafiozo [28]3 years ago
7 0

Answer:A

Step-by-step explanation:

adell [148]3 years ago
6 0

Answer:

Im pretty sure its B

Step-by-step explanation:

Up above

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Each baseball team as nine players and each football team has eleven players. Six schools have both baseball and football teams.
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6 x9= 54 and 6x11=66 so those two together equal 120 but 4x9=36 adding those would equal 156 which is the answer
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A blueprint for a picnic table has a scale of 1:20. The table in the blueprint is 3 in. long. What is the length of the actual p
blsea [12.9K]
The blue print has a scale of 1:20. So every 1 inch represents 20 inches of the actual size. so 3 inches represents 20*3 of the actual table = 60 inches
12 inches is 1 feet
so 60 inches =60/12 = 5 feet
The correct answer is 5 feet.
5 0
3 years ago
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Divide £52 in the ratio 11:2
True [87]
First, get the sum of the ratio. (11 + 2 = 13)

Divide 52 by 13 to find one 'part' of the ratio. (52 ÷ 13 = 4)

Now that we have one 'part' of the ratio, we multiply it by 11 and 2 to get: (£4 × 11 = £44) and (£4 × 2 = £8).

The ratio will be £44:8.

We can check if this is correct by adding 44 and 8 to see if it adds up to 52. (44 + 8 = 52). It does, so it's correct.
6 0
3 years ago
What is 24/7 as a mixed number
Masteriza [31]
I can't do the fraction bar but it's 3 and 3/7
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4 years ago
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A town is planning a playground. It wants to fence in a rectangular space using an existing wall. What is the greatest area it c
777dan777 [17]

Answer:

1250 ft^{2}

Step-by-step explanation:

We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.

Let the length of the rectangle be 'X' feet and width be 'Y' feet.

As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.

As, X + 2Y = 100 → X = 100 - 2Y

Now, the area of the rectangle = XY = X × ( 100 - 2Y ).

i.e Area of the rectangle = -2Y^{2} +100Y.

The general form of a quadratic equation is y=ax^{2}+bx+c.

The maximum value of a quadratic equation is given by x=\frac{-b}{2a}.

Therefore, the greatest value of -2Y^{2} +100Y is at Y = \frac{-100}{2 \times -2} = \frac{-100}{-4} = 25.

Thus, Y = 25 and X = 100 - 2Y → X = 100 - 2 × 25 → X = 50.

Hence, the area of the rectangle is XY = 50 × 25 = 1250 ft^{2}.

3 0
4 years ago
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