Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
Answer: 720 ways
Step-by-step explanation:
Given
A train has 1 main engine and remaining 6 train cars
If the engine is always in the front the remaining train cars can be arranged is

"Pedro has twice as many carrots as Martha:"
p = 2m
<span>
"If Pedro gives 5 carrots to Oliver,"
p - 5 (</span>Oliver is irrelevant.)<span>
"then Martha has 3 times as many carrots as Pedro"
</span>
m = 3(p - 5)
We know p in terms of m, so substitute it in:
m = 3(2m - 5)
Distribute the 3:
m = 6m - 15
Subtract 6m from both sides:
m-6m=-15
Combine variable terms:
-5m=-15
Divide out -5
m = -15/-5
m = 3
The answer is c) 3
Answer:
k would be 55
Step-by-step explanation:
35+90=125 and assuming that you're looking for a supplementary angle, the total must equal 180 so subtract 180-125 and you get k=55