Answer:
28 square units
Step-by-step explanation:
These vertices are written in the form of their x and y coordinates. Let
A=(1,2) ; B =(1,-5) ; C =(5, -5) ; D=(5,2)
The x points are 1, 1, 5, 5
The y points are 2,-5, -5, 2
The x extremes range from 1 to 5. The length in-between is 5-1 = 4
The y extremes range from -5 to 2. The length in-between is 2-(-5) = 7
Area of the polygon enclosed by the coordinates
= 4 x 7 = 28 square units
Answer:
32
Step-by-step explanation:
2x2=4/2=2 small triangle, 2x2=4 small square, 6x2/2=6 med. triangle, 6+2+2=10x4=40/2=20
2+4+6+20=32
Answer:
x = 2
Step-by-step explanation:
(16 = 
and 8 = 
)
Since the base number is 2, the exponents must equal each other.
So:
12x = 3x+18
9x = 18
x = 2
Hi there! :)
A radical equation is an equation in which a variable (ex. x, y, a, v) is under a radical sign. The only equation that has a variable under a radical (x) is the second option. There is an x next to the 2 under the radical.
I hope this helps, DM me if you have anymore questions. :)
~kaikers
Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
