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dolphi86 [110]
3 years ago
11

Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando

m, what is the expected value for the amount chosen
Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

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A study conducted in 2000 found that the mean number of children under 18 per household in a certain community was 1.7. A statis
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The given hypothesis are

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If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?
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Answer:

<em>B</em> (x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)

Step-by-step explanation:

<u>Dilations</u>

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

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B \mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}

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