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dolphi86 [110]
3 years ago
11

Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando

m, what is the expected value for the amount chosen
Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

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Let's solve your equation step-by-step.
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