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dolphi86 [110]
3 years ago
11

Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando

m, what is the expected value for the amount chosen
Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

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Michael got 28 out of 33 points on his math test what percent of the questions did he get correct round your answer to the neare
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28/33 × 100% = 0.84848... × 100% ≈ 85%

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Since we're not told the number of points per question, we don't actually have enough information to answer the question.

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3 years ago
Plz help me with this thank you
o-na [289]

Answers:

  • One possible equation to solve is tan(x) = 4/15
  • That solves to roughly 15 degrees

==============================================================

Explanation:

Refer to the diagram below.

The segment AB is the player's height of 6 ft.

The segment CD is the hoop's height, which is 10 ft.

There is a point E on CD such that rectangle BACE forms. This will help us form ED later.

Angle EBD is what we're after, which I'll call x.

Since the free throw line is 15 ft from the basket, this means segments EB and AC are 15 ft each.

In rectangle BACE, the side EC is opposite AB. So both of those sides are 6 ft each.

Since CD = 10 and EC = 6, this must mean ED = CD-EC = 10-6 = 4.

---------------------------------------

To summarize, we found that ED = 4 and EB = 15.

We'll focus our attention entirely on triangle EBD

We have two known legs of the triangle, specifically the opposite and adjacent sides.

So we'll use the tangent ratio.

tan(angle) = opposite/adjacent

tan(B) = ED/EB

tan(x) = 4/15 .... is the equation to solve

x = arctan(4/15) .... same as inverse tangent or \tan^{-1}

x = 14.931417 ..... make sure to be in degree mode

x = 15 ..... rounding to the nearest whole degree

So that unknown angle in the diagram is approximately 15 degrees

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3 years ago
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Answer:

I think you're answer is the correct one

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What percent of 40 is 9​
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9/40  x  100=   22.5

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What are the steps to solve the quadratic equation x^2+4x-6=0
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METHOD\ 1:\\\\Use:\\\\(*)\qquad(a+b)^2=a^2+2ab+b^2\\---------------------\\\\x^2+4x-6=0\qquad\text{add 6 to both sides}\\\\x^2+4x=6\\\\x^2+2(x)(2)=6\qquad\text{add}\ 2^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(2)+2^2}_{(*)}=6+2^2\\\\(x+2)^2=6+4\\\\(x+2)^2=10\Rightarrow x+2=\pm\sqrt{10}\qquad\text{subtract 2 from both sides}\\\\\boxed{x=-2-\sqrt{10}\ \vee\ x=-2+\sqrt{10}}

METHOD\ 2:\\\\\text{use the quadratic formula:}\\\\ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta>0,\ \text{the equation has two solutions}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\if\ \Delta=0,\ \text{then the equation has one solution:}\ x=\dfrac{-b}{2a}\\\\if\ \Delta

x^2+4x-6=0\\\\a=1,\ b=4,\ c=-6\\\\\Delta=4^2-4(1)(-6)=16+24=40>0\\\\\sqrt\Delta=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}\\\\x_1=\dfrac{-4-2\sqrt{10}}{2(1)}=\dfrac{-4}{2}-\dfrac{2\sqrt{10}}{2}=-2-\sqrt{10}\\\\x_2=\dfrac{-4+2\sqrt{10}}{2(1)}=\dfrac{-4}{2}+\dfrac{2\sqrt{10}}{2}=-2+\sqrt{10}

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3 years ago
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