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KengaRu [80]
3 years ago
11

jeff hiked for 2 hours and traveled 5 miles. If he continues at the same pace, which equation will show the relationship between

the time, t, in hours he hikes to distance, d, in miles? Will the graph be continuous or discrete? d = 0.4t, discrete d = 0.4t, continuous
Mathematics
2 answers:
Masja [62]3 years ago
6 0

Answer:

d = 2.5t, continuous

Step-by-step explanation:

5 divided by 2 is 2.5, and this would be continuous.

AfilCa [17]3 years ago
5 0
His rate = d/t because d=rt
So r = 5/2 = 2.5 mi/hr
So d = 5/2•t
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Okay, I’m pretty sire this is right.
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B: (-3, 2)
C: (-8, 3)
D: (-4, 3)

To do this problem (I am not completely confident in this) I am pretty sure you flip the signs for both the x and y values due to the rotation of the shape 180°, then add 6 to the y value.
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3 years ago
A baseball team played 154 regular season games. The ratio of the number of games they won to the number of games they lost was
Fittoniya [83]

Answer:

88 won and 66 lost

Step-by-step explanation:

Won = \frac{154}{4+3}×4 = 88 games

Lost = 154 - 88 = 66 games

7 0
3 years ago
Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans
sammy [17]

Answer:

The average rate of change of the given function

A(x) =  1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function f(x) = x² - 2x -4

And given that x = a = -1 and  x=b = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

<u><em>Step(ii):-</em></u>

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1

<u><em>final answer:-</em></u>

The average rate of change of the given function

A(x) =  1

5 0
3 years ago
Read 2 more answers
A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she
marta [7]

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

​How much water, in milliliters, does the student have left in the bottle?

Answer:

the amount of water the student have left in the bottle is 250 milliliters

Step-by-step explanation:

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

​How much water, in milliliters, does the student have left in the bottle?

Before the soccer practice, she drank 25 % of the water

25% of the water = 25% of 500

                             = 25% × 500

                              =\frac{25}{100} ×  500

At the right hand-side of the equation, the two zeros will cancel-out the other two zeros, hence;

                                = 25 × 5

                                 =125

25% of the water = 125 milliliters

From the question, it was said that drank 25% of the water before soccer, this implies that she drank 125 milliliters from the water bottles.

If she drank 125 milliliters of  from a 500 milliliters water contain in the water bottle, then the amount of water left will be 500 ml - 125 ml = 375 ml

This implies that before the soccer practice she had 375 milliliters of water left in the water bottle.

After the practice, she drank 1/3 of the remaining water, which means after the practice she drank 1/3 of 375

1/3 of 375 = \frac{1}{3} × 375 = \frac{375}{3} = 125

After the practice she drank 125 milliliters of water from her 375 milliliters water.

The amount of water she have left after the practice will be;

375 milliliters - 125 milliliters = 250 milliliters

Therefore, the amount of water the student have left in the bottle is 250 milliliters

8 0
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drek231 [11]
Isolate x.
24x = 48 - 2y

Divide by 24.
x = 2 - y/12
3 0
3 years ago
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