Answer:
Yes
Step-by-step explanation:
I think it looks right I hate when teacher give you work but no telling you how to do it
Answer:
44.47 cm² (nearest hundredth)
Step-by-step explanation:
Area of ΔABC = 1/2 x base x height
⇒ 21 = 1/2 x 7 x BC
⇒ BC = 6 cm
Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
⇒ AB² + BC² = AC²
⇒ 7² + 6² = AC²
⇒ AC² = 85
⇒ AC = √85 cm
Cosine rule to find length AD:
c² = a² + b² - 2 ab cosC
⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)
⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°
⇒ AD² - 5.39106...AD + 0.36 = 0
⇒ AD = 5.323442445, 0.06762541414
⇒ AD = 5.323442445
Area of a triangle ADC: (1/2)absinC
(where a and b are adjacent sides and C is the angle between them)
⇒ area = (1/2) × AC × AD × sin(DAC)
⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)
⇒ area =23.4675821... cm²
Area of quadrilateral = area of ΔABC + area of ΔADC
= 21 + 23.4675821...
= 44.47 cm² (nearest hundredth)
Answer:
102 boxes.
Step-by-step explanation:
102x12=1224
The question says how many *full* boxes so even though the number is not exactly 1228, the correct answer is 102 boxes. Hope this helps!
Answer:
The end of the stencil is located at (8, -1)
Step-by-step explanation:
The given parameters are;
Location of the beginning of the left edge of the stencil = (-1, 2)
Location of the detail = (2, 1)
Ratio of detail distance from beginning to detail to distance from beginning to stencil end = 1:2
Distance from beginning to detail = √((-1 - 2)² + (2 - 1)²) = √10
Given that the ratio of the length of the detail to the length of the end after the detail is 1:2 therefore;
√10:Length of stencil side = 1:2
Distance from detail to stencil end = 2×√10
Which gives;
Slope of line = tan⁺¹((2 - 1)/(-1 - 2)) = tan⁺¹(-1/3) = -18.435°
x-coordinates of the end of the stencil = 2√10 × cos(-18.435°) + 2 = 8
y coordinates of the end of the stencil = 2√10 × sin(-18.435°) + 1 = -1
The coordinates of the end of the stencil = (8, -1)
