Question

Hi guys,

Answer 1

Answer:

1587.2 g

Explanation:

First of all, we need to calculate the number of moles of oxygen. We can do it by using the equation of state for an ideal gas:

$pV=nRT$

where in this case:

$p=1.9 atm$ is the pressure of the gas

V = 640 L is the volume

n is the number of moles

$R=0.082 atm L mol^{-1} K^{-1}$ is the gas constant

$T=26^{\circ}C+273=299 K$ is the absolute temperature of the gas

Solving for n, we find:

$n=\frac{pV}{RT}=\frac{(1.9)(640)}{(0.082)(299)}=49.6 mol$

Now we can find the mass of the oxygen by using the formula:

$m=nM$

where:

n = 49.6 mol is the number of moles

M = 32 g/mol is the molar mass of molecular oxygen

Therefore, substituting,

$m=(49.6)(32)=1587.2 g$