Answer:
clf3
Explanation:
it occupied more than 8 valence electrons
Answer:
The solution is given below
Explanation:
Heat, q= mc∆T
q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C
q= -1619.75J
NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.
Enthalpy Change, ∆H = 1619.75 7/ 10.5 g
= 154.26 J/g
No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr
=10.5g/119gmol-1
=0.088 mol
∆H= 1619.75 J/ 0.088 mol
= 18.41 kJ/mol
Answer:
zero
Explanation:
I I think one should be so accurate with measurements and experiments
The problem above is simply a conversion problem. We only need a conversion factor to convert the units from amu to kg. From a conversion table, we will see that 1 amu is equal to 1.66x10^-27 kg. We convert as follows:
0.13261 amu ( <span>1.66 × 10^-27 kg / 1 amu ) = 2.20x10^-28 kg </span>